如何计算 collect() 列表中的元素并将该 count() 用于 WHERE 条件

Question

希望得到一些帮助。

有以下查询：

MATCH  (a:Academy)-[]-(w:Work)
RETURN collect(distinct a.name)as Associated_academies_for_this_book,w.shortTitle as  
       book_short_title, w.workId as Book_ID order by size(collect(distinct a.name)) desc

使用此输出： result query

我只需要 return 结果在第一列的列表中有一个以上的元素（由 collect(distinct a.name) 生成的列），我尝试使用 count(collect)>1和类似的东西，但没有得到我需要的东西。有什么想法吗？

非常感谢

Answer 1

您可以使用size

MATCH (a:Academy)-[]-(w:Work)
WITH collect(distinct a.name) as Associated_academies_for_this_book, w.shortTitle as book_short_title, w.WorkID as Book_ID 
WHERE size(Associated_academies_for_this_book)>1
RETURN book_short_title, Book_ID

或

您可以使用 count as referenced in 文档，聚合与 * 一起使用，应该会出现。

MATCH (a:Academy)-[]-(w:Work)
WITH collect(distinct a.name) as Associated_academies_for_this_book, 
     w.shortTitle as book_short_title, w.workId as Book_ID, count (*) as occ
WHERE occ>1
RETURN occ, Associated_academies_for_this_book, book_short_title, Book_ID

第二个将此信息作为 occ 变量与其他相关列存储在 WITH 语句中作为中间步骤，如果需要，您可以稍后使用它 on/in RETURN 语句。您可以使用 size 或 count 聚合。

如何计算 collect() 列表中的元素并将该 count() 用于 WHERE 条件

how to count elements inside a collect() list and use that count() for a WHERE condition

neo4j

cypher

aggregate-functions