如何遍历列表以检查项目是否是另一个列表的成员

Question

我想检查诊断代码列表中的任何项目是否存在于另一个列表中。

我是 Drools 的新手，我仍在尝试确定最佳方法，因为当前的方法不起作用（当它应该返回 'true' 时，输出显示为 null）。

Java POJO

public class EligibilityDomainObject {
    
    private List<String> listOfString;  
    public List<String> getListOfString() {  
         return listOfString;  
    }  
    public void setListOfString(List<String> listOfString) {  
         this.listOfString = listOfString;  
    }  
    public void addString(String value) {  
         if (listOfString == null) {  
              listOfString = new ArrayList<String>();  
         }  
         listOfString.add(value);  
    }  
    private Boolean isComplexPhysicalHealth;
    public Boolean getIsComplexPhysicalHealth() {
        return this.isComplexPhysicalHealth;
    }

    public void setIsComplexPhysicalHealth(Boolean isComplexPhysicalHealth) {
        this.isComplexPhysicalHealth = isComplexPhysicalHealth;
    }

流口水

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject($listOfString : listOfString,
            $listOfString memberOf "F77 EOO F99" )
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
end

主要

    public static void main(String[] args) {
        SpringApplication.run(RulesEngineApplication.class, args);
        

        try {
            KieServices kieServices = KieServices.Factory.get();
            KieContainer kContainer = kieServices.getKieClasspathContainer();

            KieSession kSession = kContainer.newKieSession("ksession-rules");
            
            EligibilityDomainObject eligibilityDomainObject = new EligibilityDomainObject(null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null);

            eligibilityDomainObject.addString("F77");
            eligibilityDomainObject.addString("F99");
            System.out.println("List of diagnosis codes: "+ eligibilityDomainObject.getListOfString().toString());
            kSession.insert(eligibilityDomainObject);
            kSession.fireAllRules();
            System.out.println("complex phys health flag: "+ eligibilityDomainObject.getIsComplexPhysicalHealth());
            
            kSession.dispose(); 
        } catch (Throwable t) {
            t.printStackTrace();
        }
    }

输出

List of diagnosis codes: [Z590, E0800]

complex phys health flag: null

预期输出

List of diagnosis codes: [Z590, E0800]

complex phys health flag: true

Answer 1

我能够使用 'from' 关键字解决它

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject($listOfString : listOfString)
            value: String(value memberOf "F77 EOO F99" ) from $listOfString
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
end

Answer 2

您的规则将不符合 'F'、'F7'、'F9'...

考虑其他几种方法：

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject($listOfString : listOfString)
            value: String(value in ("F77", "EOO", "F99") ) from $listOfString
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
end

根据documentation，需要

Avoid using the from element when you can insert all facts into the working memory of the Drools engine or use nested object references in your constraint expressions."

以下将导致每个 EligibilityDomainObject 仅触发一次规则，而不是每个匹配值：

import static org.apache.commons.collections4.CollectionUtils.containsAny;

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject(containsAny(listOfString, "F77", "EOO", "F99"))
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
end

一次收集匹配值

import static org.apache.commons.collections4.CollectionUtils.intersection;
import static com.google.common.collect.Sets.newHashSet;

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject(
            $values : intersection(listOfString, newHashSet("F77", "EOO", "F99")), 
            !$values.isEmpty())
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
        System.out.println($values);
end

如何遍历列表以检查项目是否是另一个列表的成员

How to loop through a list to check if an item is a memberOf another list

java

drools