从 PHP 中的数组创建树结构

Question

我有一个这样的数组：

array(
      array(id => 7, parent_id => 0, name => Current Assets)
      array(id => 8, parent_id => 0, name => Fixed Assets)
      array(id => 18, parent_id => 7, name => Assets)
      array(id => 38, parent_id => 18, name => Receivable)
      array(id => 38, parent_id => 18, name => Inventory)
      array(id => 39, parent_id => 0, name => Landed Cost Of Inventory)
      array(id => 40, parent_id => 38, name => Jazz Cash)
      array(id => 41, parent_id => 39, name => Advance to Vendors)
)

现在我需要一些有效的方法将其转换成这样的树结构。

array(
      array(id => 7, parent_id => 0, name => Current Assets, level=>0)
      array(id => 8, parent_id => 0, name => Fixed Asset, level => )
      array(id => 18, parent_id => 7, name => Assets, level => 1)
      array(id => 38, parent_id => 18, name => Inventory, level => 2)
      array(id => 39, parent_id => 0, name => Landed Cost Of Inventory, level => 0)
      array(id => 40, parent_id => 38, name => Jazz Cash, level => 3)
      array(id => 41, parent_id => 39, name => Advance to Vendors, level => 1)
)

我不需要向左或向右添加它们，我只需要将传递给 jQgrid 的简单级别。

Answer 1

按照parent -> child的顺序收集所有的id在一个数组中，其中parent_id是键，它有一个包含所有子id的数组。第二步是遍历树并分配等级。

<?php

function assignLevels(&$data){
    $kids = [];

    foreach($data as $d){
        $kids[ $d['parent_id'] ] = $kids[ $d['parent_id'] ] ?? [];
        $kids[ $d['parent_id'] ][] = $d['id'];
    }
    
    $data = array_column($data, null, 'id');
    traverseTree($kids, 0, $data);
    $data = array_values($data);
}


function traverseTree($kids, $id, &$data, $level = 0){
    foreach($kids[ $id ] as $sub_id){
        $data[ $sub_id ]['level'] = $level;
        if(isset($kids[ $sub_id ] )) traverseTree($kids, $sub_id, $data, $level + 1);
    }
}

assignLevels($data);

print_r($data);

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从 PHP 中的数组创建树结构

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