Django

Question

我想显示未在模板中预订约会的日期。出于这个原因，我到目前为止：

# Collect only the dates so that i can find what is not in that range.
example_dates = Appointment.objects.values_list('start_appointment', flat=True)

# Initialize start and end date
start_date = datetime.date.today()
end_date = start_date + datetime.timedelta(days=5)

# Initialize new list that will include records does not exists
not_found_dates = []

# Loop through in date range and if date does not exists 
# Create a dict and add it to the list
for n in range(int((end_date - start_date).days)):
    new_date = start_date + datetime.timedelta(days=n)
    if new_date not in not_found_dates:
        not_found_dates.append(new_date)
        print(new_date)

# Get original queryset
examples = Appointment.objects.filter(start_appointment__range=(start_date, end_date)).values('start_appointment')
print(examples)

# Convert it to a list
examples = list(examples)

return render(request, 'appointments/add-appointment.html', {'examples': examples, 'not_found_dates': not_found_dates})

当我从循环中打印 new_date 时，我得到： 2021-11-22 2021-11-23 2021-11-24 2021-11-25 2021-11-26

以及来自 examples returns 的查询，我在 2021-11-23 的 (2) 和 2021-11-22 的 (1) 范围内在数据库中有 3 个约会。

是否可以显示未预约的日期，即 2021-11-24、2021-11-25、2021-11-26。

Answer 1

您将获得定义时间范围内的日期列表（持续时间 num_days），其中日期不属于查询的一部分：

from datetime import date, timedelta

num_days = 5
start_date = date.today()
timeframe = [start_date + timedelta(days=d) for d in range(num_days)]
exclude = list(Transaction.objects.values_list("start_appointment", flat=True).distinct())

set(timeframe) - set(exclude)

Django - 显示约会日期

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