Javascript - 异步函数中的异步函数不等待回答？

Question

问题

异步函数中的异步函数不等待？

代码

// onConfirmed executes after confirming on modal
onConfirmed={async () => {
  const res = await submit(submitData) // post data and return some data
  if (!res.error) {
    const resFb= await Fb(data)
    console.log(resFb) // ***execute it before waiting "await Fb(data)"
  } else {
  // handle error
  }
}}

//Fb function
export const Fb = async (data) => {
  const body = {
    method: 'share',
    href: 'https://hogehoge',
    display: 'popup',
    hashtag: '#hogehoge',
    quote: `content: ${data.content}`,
  }
  return FB.ui(body, async (res) => {
    if (res !== undefined && !res.error_code) {
      return await Api.put(body) // put to own server (executes here without problem)
    } else {
      return res
    }
  })
}

facebook SDK (FB.ui())

我需要获取等待异步函数的 resFb 的正确值。

Answer 1

FB.ui() 没有 return 承诺，因此由 Fb() 编辑的承诺 return 将立即解决，并且传递给 FB.ui 的回调将稍后仍然执行...

对于 return 只有在执行该回调时才解析的承诺，promisify FB.ui:

export const Fb = (data) => {
  const body = {
    method: 'share',
    href: 'https://hogehoge',
    display: 'popup',
    hashtag: '#hogehoge',
    quote: `content: ${data.content}`,
  };
  return new Promise(resolve => 
    FB.ui(body, res =>
      resolve(!res?.error_code ? Api.put(body) : res)
    )
  );
}