如何计算 pandas 数据框中两个站的纬度和经度之间的距离

Question

我有一个包含站信息的数据框，包括纬度和经度，如下所示：

start_lat   start_lng   end_lat      end_lng
41.877726   -87.654787  41.888716   -87.644448
41.930000   -87.700000  41.910000   -87.700000
41.910000   -87.690000  41.930000   -87.700000

和聪明人一样。

我想根据这些信息创建一个距离列，其中这些起点和终点之间的距离可以是公里或英里。

（如下亲分享，当我尝试执行SO答案时遇到错误。）

from math import sin, cos, sqrt, atan2
dlon = data.end_lng - data.start_lng
dlat = data.end_lat - data.start_lat

a = ((sin(dlat/2))**2 + cos(lat1) * cos(lat2) * (sin(dlon/2))**2)
c = 2 * atan2(sqrt(a), sqrt(1-a))
data['distance'] = R * c

TypeError                                 Traceback (most recent call last)
<ipython-input-8-a8f8b698a81b> in <module>()
      2 dlon = data.end_lng - data.start_lng
      3 dlat = data.end_lat - data.start_lat
----> 4 a = ((sin(dlat/2))**2 + cos(lat1) * cos(lat2) * (sin(dlon/2))**2).apply(lambda x: float(x))
      5 c = 2 * atan2(sqrt(a), sqrt(1-a))
      6 data['distance'] = R * c

/usr/local/lib/python3.7/dist-packages/pandas/core/series.py in wrapper(self)
    127         if len(self) == 1:
    128             return converter(self.iloc[0])
--> 129         raise TypeError(f"cannot convert the series to {converter}")
    130 
    131     wrapper.__name__ = f"__{converter.__name__}__"

TypeError: cannot convert the series to <class 'float'>

如何解决？

Answer 1

您需要对每一行进行计算，一种方法是使用 itterows（不保证距离计算本身）：

def get_distance(row, R = 6371): #km
    dlon = row[1]['end_lng'] - row[1]['start_lng']
    dlat = row[1]['end_lat'] - row[1]['start_lat']

    a = ((sin(dlat/2))**2 + cos(row[1]['start_lat']) * cos(row[1]['end_lat']) * (sin(dlon/2))**2)
    c = 2 * atan2(sqrt(a), sqrt(1-a))
    return R * c

data['distance'] = [get_distance(row) for row in data.iterrows()]

如何计算 pandas 数据框中两个站的纬度和经度之间的距离

How to calculate the distance between latitudes and longitudes of two stations in a pandas dataframe

python-3.x

pandas

dataframe

distance

latitude-longitude