SQL JOIN return 仅第一场比赛

Question

我觉得这是一道基础题，但是我想不通。我是新手所以请多多包涵。

我正在分析来自 FIFA 比赛的球员数据，我想得到一个 table 每个球员的最高评分和发生这种情况的最早年龄。

这是数据示例：

id	name	position	rating	age
1	James	RW	70	20
1	James	RW	71	21
2	Frank	CB	73	23
2	Frank	CB	73	24
3	Miles	CM	75	27
3	Miles	CM	74	28

这是查询应该return:

id	name	position	rating	age
1	James	RW	71	21
2	Frank	CB	73	23
3	Miles	CM	75	27

我想我可以先得到每个球员的最高总分，然后 JOIN 得到年龄，但这给了其他年份一个球员有相同的最高评价。

id	name	position	rating	age
1	James	RW	71	21
2	Frank	CB	73	23
2	Frank	CB	73	24
3	Miles	CM	75	27

谢谢，

Answer 1

试试这个（可能会快一点）：

with mytable as (
    select 1 as id, "James" as name, "RW" as position, 70 as rating,  20 as age union all 
    select 1, "James", "RW", 71, 21 union all
    select 2, "Frank", "CB", 73, 23 union all
    select 2, "Frank", "CB", 73, 24 union all
    select 3, "Miles", "CM", 75, 27 union all
    select 3, "Miles", "CM", 74, 28
)
select array_agg(t order by rating desc, age asc limit 1)[OFFSET(0)].*,
from mytable as t
group by t.id

Answer 2

一种方法使用 ROW_NUMBER 和 QUALIFY:

SELECT *
FROM yourTable
WHERE true
QUALIFY ROW_NUMBER() OVER (PARTITION BY id ORDER BY rating DESC, age) = 1;

Answer 3

如果你愿意，也试试这个。我想这就是你需要的。

select p1.id,
       p1.name,
       p1.pos,
       max(p1.rating),
       p1.age
  from players p1
  join (select name, min(age) min_age
          from players 
         group by 1) p2 on p1.name = p2.name and p1.age = p2.min_age
 group by p1.id, p1.name, p1.pos, p1.age

SQL JOIN return 仅第一场比赛

SQL JOIN return only the first match

sql

join

google-bigquery