替换字段

Question

我正在使用以下代码：

function my_map_field( $data ) {
    $map = array(
        'Toys for 12 years old' => '12+',
        'Toys for 4 years old' => '4+',
        'Toys for 7 years old' => '7+',
        'Toys for 9 years old' => '9+',
    );
    return isset( $map[$data] ) ? $map[$data] : null;
}

它取代：12岁玩具---> 12+

如果字段包含 ('12 年')

，我需要将确切的文本映射 ('Toys for 12 years old') 更改为

例如：如果该字段包含 12 年 写 12+；如果该字段包含 7 年 ，请填写 7+。如果没有找到，留空

谢谢

Answer 1

准确匹配单词

function my_map_field( $data ) {
    $map = array(
        'Toys for 12 years old' => '12+',
        'Toys for 4 years old' => '4+',
        'Toys for 7 years old' => '7+',
        'Toys for 9 years old' => '9+',
    );

    foreach ($map as $text => $number) {
        if (stripos($text, $data) !== false) {
            return $map[$text];
        }
    }
    return '';
}

echo my_map_field('7 years');// result is 7+
echo my_map_field('11 years');// result is empty
echo my_map_field('12 years');// result is 12+

匹配任意数字与年份[s]

function my_map_field( $data ) {
    $map = array(
        'Toys for 12 years old' => '12+',
        'Toys for 4 years old' => '4+',
        'Toys for 7 years old' => '7+',
        'Toys for 9 years old' => '9+',
    );

    preg_match('/(\d+)\s*year[s]?/i', $data, $matches);
    $matchNumber = ($matches[1] ?? '');

    foreach ($map as $text => $number) {
        if (stripos($text, $matchNumber) !== false) {
            return $map[$text];
        }
    }
    return '';
}

echo my_map_field('buy toys for 12 years old');// get 12+
echo my_map_field('used toys for 12 years old');// get 12+
echo my_map_field('buy toys for 15 years old');// get empty.

替换字段

Replace the field

php

wpallimport

准确匹配单词

匹配任意数字与年份[s]