如何在同一视图中处理同一实体类型的多个表单

Question

我想为 table（只有两个字段）中的所有条目生成一个表单列表，只有一个保存和一个删除按钮。

这是屏幕：https://i.imgur.com/4hW48Bw.png

这是表格部分：

templates\item\brand\_brandForm.html.twig

{{ form_start(formView) }}
<div class="row justify-content-md-center">
    <div class="col col-lg-auto">
        #
        <br>
        {{brandId}}
    </div>
    <div class="col col-lg-3">
        {{ form_row(formView.fullname) }}
    </div>
    <div class="col col-lg-3">
        {{ form_row(formView.icon) }}
    </div>
    <div class="col col-lg-3 align-self-end">
        <button class="btn btn-primary" type="submit" name="update_button" value="{{brandId}}">
            <i class="fas fa-save"></i>
        </button>
        <button class="btn btn-danger" type="submit" name="delete_button" value="{{brandId}}">
            <i class="fas fa-trash-alt"></i>
        </button>
    </div>
</div>
{{ form_end(formView) }}

这是视图：

templates\item\brand\listForm.html.twig

{% extends 'base.html.twig' %}

{% block title %}Create a brand
{% endblock %}

{% block body %}
    <h1>Brand list form</h1>
    {% for form in forms %}
        {{form | raw}}
    {% endfor %}
{% endblock %}

这是表单类型：

class BrandType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options): void
    {
        $builder
            ->add('fullname')
            ->add('icon');
    }

    public function configureOptions(OptionsResolver $resolver): void
    {
        $resolver->setDefaults([
            'data_class' => Brand::class,
        ]);
    }
}

最后是控制器部分：

 public function editableList(EntityManagerInterface $em, Request $request, BrandRepository $brandRepository)
    {
        $formHtml = [];
        $brands = $brandRepository->findAll();
        foreach ($brands as $brand) {
            $form = $this->createForm(BrandType::class, $brand);
            $form->handleRequest($request);
            if ($form->isSubmitted()) {
                dd($brand);
            }
            $formHtml[] = $this->renderView('item/brand/_brandForm.html.twig', [
                'formView' => $form->createView(),
                'brandId' => $brand->getId(),
            ]);
        }
        return $this->render('item/brand/listForm.html.twig', [
            'forms' => $formHtml,
        ]);
    }

表单已正确生成，但是当我提交其中一个表单时，它 returns 提交数据正确但 ID 错误的实体（数据库返回的第一个 ID）。

我试图弄清楚如何将 ID 传递给 POST 请求，但我被卡住了，因为我无法在提交的实体上设置 ID。也许我走错了路，但我确定我不会错过满足我需求的选项。

欢迎提出任何建议 ;)

Answer 1

我终于找到了解决办法。诀窍是简单地创建以 ID 作为名称的命名表单。我用工厂来做。

这里是固定控制器:

/**
 * @Route("admin/item/brand/editable-list", name="admin_item_brand_editable-list")
 */
public function editableList(FormFactoryInterface $formFactoryInterface, EntityManagerInterface $em, Request $request, BrandRepository $brandRepository)
{
    $formHtml = [];
    $brands = $brandRepository->findAll();
    foreach ($brands as $brand) {
        $form = $formFactoryInterface->createNamedBuilder($brand->getId(), BrandType::class, $brand)->getForm();
        $form->handleRequest($request);
        if ($form->isSubmitted()) {
            if ($form->get('saveButton')->isClicked()) {
                $em->flush();
                $formHtml[] = $this->renderView('item/brand/_brandForm.html.twig', [
                    'formView' => $form->createView(),
                    'brandId' => $brand->getId(),
                ]);
            } elseif ($form->get('deleteButton')->isClicked()) {
                $em->remove($brand);
                $em->flush();
            } else {
                throw new ErrorException('un bouton doit être clické');
            }
        } else {
            $formHtml[] = $this->renderView('item/brand/_brandForm.html.twig', [
                'formView' => $form->createView(),
                'brandId' => $brand->getId(),
            ]);
        }
    }
    return $this->render('item/brand/listForm.html.twig', [
        'forms' => $formHtml,
    ]);
}

如何在同一视图中处理同一实体类型的多个表单

How to handle multiple form for the same entity type in the same view

forms

twig

entity

symfony5