如何在 C# 中以相同的方式 randomize/shuffle 两个数组
How to randomize/shuffle two arrays in the same way in c#
我有两个数组,一个是 PictureBox 数组,另一个是 Integer 数组,两者都具有相同数量的元素。我希望每次都随机打乱两个数组,但都以相同的方式打乱。
如果我使用两个 PictureBox 数组或两个 Integer 数组,这是一个有效的代码,但是我希望它随机排列一个 PictureBox 数组和一个 Integer 数组。
这是我要使用的代码:(两个不同的数组)
PictureBox[] cards = new PictureBox[13];
// PictureBox[] numValue = new PictureBox[13];
int[] numbers = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10 };
Random rnd = new Random();
for (int i = 0; i < cards.Length - 1; i++)
{
int j = rnd.Next(i, cards.Length);
PictureBox temp = cards[j];
cards[j] = cards[i];
cards[i] = temp;
temp = numbers[j]; //An error occurs here because numbers is not a PictureBox variable
numbers[j] = numbers[i];
numbers[i] = temp;
}
这是有效的代码:(对于相同的数组)
PictureBox[] numValue = new PictureBox[13];
PictureBox[] cards = new PictureBox[13];
// int[] numbers = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10 };
Random rnd = new Random();
for (int i = 0; i < cards.Length - 1; i++)
{
int j = rnd.Next(i, cards.Length);
PictureBox temp = cards[j];
cards[j] = cards[i];
cards[i] = temp;
temp = numValue [j];
numValue [j] = numValue [i];
numValue [i] = temp;
}
如果您知道另一个可以帮助我的不同代码,请随时分享!
只需创建两个临时变量
for (int i = 0; i < cards.Length - 1; i++)
{
int j = rnd.Next(i, cards.Length);
PictureBox tempPictureBox = cards[j]; // One for PictureBox
cards[j] = cards[i];
cards[i] = tempPictureBox;
int tempInt = numValue[j]; // Another one for int
numValue[j] = numValue[i];
numValue[i] = tempInt;
}
如果你想要一个可以在任何集合上使用的洗牌器,你可以创建这样一个 class。
public class Shuffler
{
private List<Guid> order;
private List<Guid> createOrder(int count)
{
return Enumerable.Range(0, count)
.Select(i => Guid.NewGuid())
.ToList();
}
public Shuffler(int count)
{
order = createOrder(count);
}
public void Reshuffle()
{
order = createOrder(order.Count);
}
public IEnumerable<T> Shuffle<T>(IEnumerable<T> collection)
{
return collection.Zip(order)
.OrderBy(e => e.Second)
.Select(e => e.First);
}
}
当您创建 Shuffler
的实例时,它会在内部创建一个列表或伪随机元素(这里是 Guid
s,但它可以是随机选择的整数,或者您想要的任何东西像)。
要打乱集合,只需将其传递给 Shuffle
方法即可。每个通过的集合都将以完全相同的方式重新排序。
它可以改进,例如它期望每个集合将具有相同数量的元素,并且将这个数量传递给 Shuffler
构造函数,这可以放宽。也没有查错,不过应该能给个大概原理吧。
这是一个用法示例。你可以在Linqpad中试试。
void Main()
{
// The test collections of different types.
var cards = Enumerable.Range(0, 13)
.Select(i => new PictureBox { Foo = $"{i}"})
.ToArray();
var numbers = Enumerable.Range(0, 13)
.ToArray();
// Creation of the Shuffler instance
var shuffler = new Shuffler(cards.Length);
// Using the Shuffler instance to shuffle collections.
// Any number of collections can be shuffled that way, in the same exact way.
cards = shuffler.Shuffle(cards).ToArray();
numbers = shuffler.Shuffle(numbers).ToArray();
// Display results.
cards.Dump();
numbers.Dump();
// Perform a new shuffle using the same Shuffler instance.
shuffler.Reshuffle();
// Again use the Shuffler to shuffle the collections.
cards = shuffler.Shuffle(cards).ToArray();
numbers = shuffler.Shuffle(numbers).ToArray();
// Display results.
cards.Dump();
numbers.Dump();
}
// You can define other methods, fields, classes and namespaces here
public class PictureBox
{
public string Foo { get; set; }
}
public class Shuffler
{
private List<Guid> order;
private List<Guid> createOrder(int count)
{
return Enumerable.Range(0, count)
.Select(i => Guid.NewGuid())
.ToList();
}
public Shuffler(int count)
{
order = createOrder(count);
}
public void Reshuffle()
{
order = createOrder(order.Count);
}
public IEnumerable<T> Shuffle<T>(IEnumerable<T> collection)
{
return collection.Zip(order)
.OrderBy(e => e.Second)
.Select(e => e.First);
}
}
一个结果集:
cards number
"12" 12
"1" 1
"0" 0
"11" 11
"3" 3
"2" 2
"9" 9
"5" 5
"10" 10
"8" 8
"4" 4
"7" 7
"6" 6
具有静态字段的纯静态 class 和 Shuffle
扩展方法也可以按照相同的原则制作。
我有两个数组,一个是 PictureBox 数组,另一个是 Integer 数组,两者都具有相同数量的元素。我希望每次都随机打乱两个数组,但都以相同的方式打乱。
如果我使用两个 PictureBox 数组或两个 Integer 数组,这是一个有效的代码,但是我希望它随机排列一个 PictureBox 数组和一个 Integer 数组。
这是我要使用的代码:(两个不同的数组)
PictureBox[] cards = new PictureBox[13];
// PictureBox[] numValue = new PictureBox[13];
int[] numbers = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10 };
Random rnd = new Random();
for (int i = 0; i < cards.Length - 1; i++)
{
int j = rnd.Next(i, cards.Length);
PictureBox temp = cards[j];
cards[j] = cards[i];
cards[i] = temp;
temp = numbers[j]; //An error occurs here because numbers is not a PictureBox variable
numbers[j] = numbers[i];
numbers[i] = temp;
}
这是有效的代码:(对于相同的数组)
PictureBox[] numValue = new PictureBox[13];
PictureBox[] cards = new PictureBox[13];
// int[] numbers = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10 };
Random rnd = new Random();
for (int i = 0; i < cards.Length - 1; i++)
{
int j = rnd.Next(i, cards.Length);
PictureBox temp = cards[j];
cards[j] = cards[i];
cards[i] = temp;
temp = numValue [j];
numValue [j] = numValue [i];
numValue [i] = temp;
}
如果您知道另一个可以帮助我的不同代码,请随时分享!
只需创建两个临时变量
for (int i = 0; i < cards.Length - 1; i++)
{
int j = rnd.Next(i, cards.Length);
PictureBox tempPictureBox = cards[j]; // One for PictureBox
cards[j] = cards[i];
cards[i] = tempPictureBox;
int tempInt = numValue[j]; // Another one for int
numValue[j] = numValue[i];
numValue[i] = tempInt;
}
如果你想要一个可以在任何集合上使用的洗牌器,你可以创建这样一个 class。
public class Shuffler
{
private List<Guid> order;
private List<Guid> createOrder(int count)
{
return Enumerable.Range(0, count)
.Select(i => Guid.NewGuid())
.ToList();
}
public Shuffler(int count)
{
order = createOrder(count);
}
public void Reshuffle()
{
order = createOrder(order.Count);
}
public IEnumerable<T> Shuffle<T>(IEnumerable<T> collection)
{
return collection.Zip(order)
.OrderBy(e => e.Second)
.Select(e => e.First);
}
}
当您创建 Shuffler
的实例时,它会在内部创建一个列表或伪随机元素(这里是 Guid
s,但它可以是随机选择的整数,或者您想要的任何东西像)。
要打乱集合,只需将其传递给 Shuffle
方法即可。每个通过的集合都将以完全相同的方式重新排序。
它可以改进,例如它期望每个集合将具有相同数量的元素,并且将这个数量传递给 Shuffler
构造函数,这可以放宽。也没有查错,不过应该能给个大概原理吧。
这是一个用法示例。你可以在Linqpad中试试。
void Main()
{
// The test collections of different types.
var cards = Enumerable.Range(0, 13)
.Select(i => new PictureBox { Foo = $"{i}"})
.ToArray();
var numbers = Enumerable.Range(0, 13)
.ToArray();
// Creation of the Shuffler instance
var shuffler = new Shuffler(cards.Length);
// Using the Shuffler instance to shuffle collections.
// Any number of collections can be shuffled that way, in the same exact way.
cards = shuffler.Shuffle(cards).ToArray();
numbers = shuffler.Shuffle(numbers).ToArray();
// Display results.
cards.Dump();
numbers.Dump();
// Perform a new shuffle using the same Shuffler instance.
shuffler.Reshuffle();
// Again use the Shuffler to shuffle the collections.
cards = shuffler.Shuffle(cards).ToArray();
numbers = shuffler.Shuffle(numbers).ToArray();
// Display results.
cards.Dump();
numbers.Dump();
}
// You can define other methods, fields, classes and namespaces here
public class PictureBox
{
public string Foo { get; set; }
}
public class Shuffler
{
private List<Guid> order;
private List<Guid> createOrder(int count)
{
return Enumerable.Range(0, count)
.Select(i => Guid.NewGuid())
.ToList();
}
public Shuffler(int count)
{
order = createOrder(count);
}
public void Reshuffle()
{
order = createOrder(order.Count);
}
public IEnumerable<T> Shuffle<T>(IEnumerable<T> collection)
{
return collection.Zip(order)
.OrderBy(e => e.Second)
.Select(e => e.First);
}
}
一个结果集:
cards number
"12" 12
"1" 1
"0" 0
"11" 11
"3" 3
"2" 2
"9" 9
"5" 5
"10" 10
"8" 8
"4" 4
"7" 7
"6" 6
具有静态字段的纯静态 class 和 Shuffle
扩展方法也可以按照相同的原则制作。