如何迭代 TypeScript 中已知的 属性 键?
How to iterate over known property keys in TypeScript?
这是我的代码:
interface Siswa {
name: string,
points: { a: number, b: number, c: number, d?: number, e?: number }
}
function find_average_points(data: Array<Siswa>): Array<{name: string, average: number}> {
let returned_array: Array<{name: string, average: number}> = [];
data.forEach((item: Siswa) => {
let sum: number = 0;
let keys = Object.keys(item.points);
keys.forEach((key: any) => sum+=item.points[key]);
returned_array.push({name: item.name, average: (sum/keys.length)});
});
return returned_array;
}
当我在 JavaScript 中尝试此函数时,它 运行 正确并且结果是我想要的,但是在 TypeScript 中,我在 item.points[key]
中遇到错误。它说:
Element implicitly has an 'any' type because expression of type 'string' can't be used to index type '{ a: number; b: number; c: number; d?: number | undefined; e?: number | undefined; }'.
No index signature with a parameter of type 'string' was found on type '{ a: number; b: number; c: number; d?: number | undefined; e?: number | undefined; }'
不知道什么意思
可以结合使用keyof和null检查来解决问题。
interface Points { a: number, b: number, c: number, d?: number, e?: number } // only did to use keyof
interface Siswa {
name: string,
points: Points
}
function find_average_points(data: Array<Siswa>): Array<{name: string, average: number}> {
let returned_array: Array<{name: string, average: number}> = [];
data.forEach((item: Siswa) => {
let sum: number = 0;
let keys = Object.keys(item.points) as (keyof Points)[]; // use this if you know you wont add extra non number properties in Point
keys.forEach((key) => sum+=item.points[key] ?? 0); // for d and e with are optional
returned_array.push({name: item.name, average: (sum/keys.length)});
});
return returned_array;
}
let obj: Siswa = { name: 'Paris', points: { a: 2 , b:2, c: 4, d: 4 }} // can not add random stuff type safe
console.log(find_average_points([obj]))
使用 Object.keys()
returns 类型 string[]
(如 中所述)。相反,您可以为 points
对象中的已知键创建数组,使用它们来构建您的类型,然后在对值求和时循环遍历这些键:
const definitePoints = ['a', 'b', 'c'] as const;
const maybePoints = ['d', 'e'] as const;
type Points = (
Record<typeof definitePoints[number], number>
& Partial<Record<typeof maybePoints[number], number>>
);
interface Siswa {
name: string,
points: Points;
}
interface SiswaAverage {
name: string;
average: number;
}
function find_average_points (data: Array<Siswa>): Array<SiswaAverage> {
const result: Array<SiswaAverage> = [];
for (const {name, points} of data) {
let sum = 0;
let count = 0;
for (const point of [...definitePoints, ...maybePoints]) {
const value = points[point];
if (typeof value !== 'number') continue;
sum += value;
count += 1;
}
result.push({name, average: sum / count});
}
return result;
}
这是我的代码:
interface Siswa {
name: string,
points: { a: number, b: number, c: number, d?: number, e?: number }
}
function find_average_points(data: Array<Siswa>): Array<{name: string, average: number}> {
let returned_array: Array<{name: string, average: number}> = [];
data.forEach((item: Siswa) => {
let sum: number = 0;
let keys = Object.keys(item.points);
keys.forEach((key: any) => sum+=item.points[key]);
returned_array.push({name: item.name, average: (sum/keys.length)});
});
return returned_array;
}
当我在 JavaScript 中尝试此函数时,它 运行 正确并且结果是我想要的,但是在 TypeScript 中,我在 item.points[key]
中遇到错误。它说:
Element implicitly has an 'any' type because expression of type 'string' can't be used to index type '{ a: number; b: number; c: number; d?: number | undefined; e?: number | undefined; }'.
No index signature with a parameter of type 'string' was found on type '{ a: number; b: number; c: number; d?: number | undefined; e?: number | undefined; }'
不知道什么意思
可以结合使用keyof和null检查来解决问题。
interface Points { a: number, b: number, c: number, d?: number, e?: number } // only did to use keyof
interface Siswa {
name: string,
points: Points
}
function find_average_points(data: Array<Siswa>): Array<{name: string, average: number}> {
let returned_array: Array<{name: string, average: number}> = [];
data.forEach((item: Siswa) => {
let sum: number = 0;
let keys = Object.keys(item.points) as (keyof Points)[]; // use this if you know you wont add extra non number properties in Point
keys.forEach((key) => sum+=item.points[key] ?? 0); // for d and e with are optional
returned_array.push({name: item.name, average: (sum/keys.length)});
});
return returned_array;
}
let obj: Siswa = { name: 'Paris', points: { a: 2 , b:2, c: 4, d: 4 }} // can not add random stuff type safe
console.log(find_average_points([obj]))
使用 Object.keys()
returns 类型 string[]
(如 points
对象中的已知键创建数组,使用它们来构建您的类型,然后在对值求和时循环遍历这些键:
const definitePoints = ['a', 'b', 'c'] as const;
const maybePoints = ['d', 'e'] as const;
type Points = (
Record<typeof definitePoints[number], number>
& Partial<Record<typeof maybePoints[number], number>>
);
interface Siswa {
name: string,
points: Points;
}
interface SiswaAverage {
name: string;
average: number;
}
function find_average_points (data: Array<Siswa>): Array<SiswaAverage> {
const result: Array<SiswaAverage> = [];
for (const {name, points} of data) {
let sum = 0;
let count = 0;
for (const point of [...definitePoints, ...maybePoints]) {
const value = points[point];
if (typeof value !== 'number') continue;
sum += value;
count += 1;
}
result.push({name, average: sum / count});
}
return result;
}