有没有办法在Java中做24小时格式和60分钟格式？

Question

if(ExcessTimeHours >= 24) {
    ExcessTimeHours = 0;
}
if(ExcessTimeMin >= 60) {
    ExcessTimeMin = 0;
    ExcessTimeHours ++;
}

我添加了第一部电影开始的时间，然后我添加了那部电影的时长，然后我添加了第二部电影的开始时间，还添加了这部电影的时长，程序会告诉我是否可以看两部电影都没有问题，或者我是否会错过电影的某些分钟，或者我无法完成。

我的问题是，当时间超过午夜并从 24 小时跳到 0 小时时，我不知道如何解决这个问题。无法弄清楚条件。

    System.out.println("Start of movie A:");
    
    System.out.print("hour: ");                         // 17; 23; 0
    int startHourA = s.nextInt();
    System.out.print("min: ");                          // 30; 30; 30
    int startMinA = s.nextInt();
    
    System.out.println("Length of movie A:");
    
    System.out.print("hour: ");                         // 2; 2; 2
    int lengthHourA = s.nextInt();
    System.out.print("min: ");                          // 0; 0; 1
    int lengthMinA = s.nextInt();
    
    
    System.out.println("Start of movie B:");
    
    System.out.print("hour: ");                         // 20; 0; 0
    int startHourB = s.nextInt();
    System.out.print("min: ");                          // 0; 20; 31
    int startMinB = s.nextInt();
    
    System.out.println("Length of movie B:");
    
    System.out.print("hour: ");                         // 0; 1; 2
    int lengthHourB = s.nextInt();
    System.out.print("min: ");                          // 35; 35; 0
    int lengthMinB = s.nextInt();


    int timeBetweenMoviesHour = startHourB - ExcessTimeHours;
    int timeBetweenMoviesMin = startMinB - ExcessTimeMin;

    if (timeBetweenMoviesHour == 0 && timeBetweenMoviesMin >= 0) {
        System.out.println("Recommendation: No problem");
    }
    else if (timeBetweenMoviesMin > 0) {
        System.out.println("Recommendation: You won't see " + 
        timeBetweenMoviesMin + " minutes");
    }
    else System.out.println("Recommendation: You can't make it");

Answer 1

java.time

您将要使用 LocalTime 和 Duration 类。例如像下面这样。我不认为我的代码完全符合您希望您的代码执行的操作，但它应该可以帮助您入门。

    // Convert inputs to LocalTime and Duration objects

    LocalTime startMovieA = LocalTime.of(16, 0);
    Duration lengthMoviaA = Duration.ofHours(2).plusMinutes(15);

    LocalTime startMovieB = LocalTime.of(18, 45);

    // Do calculations

    LocalTime endMovieA = startMovieA.plus(lengthMoviaA);
    Duration timeBetweenMovies = Duration.between(endMovieA, startMovieB);

    // Output

    if (timeBetweenMovies.isNegative()) {
        System.out.println("You will be missing " + timeBetweenMovies.abs());
    }
    else if (timeBetweenMovies.isZero()) {
        System.out.println("You will just make it");
    }
    else {
        System.out.println("You will have " + timeBetweenMovies + " between the movies");
    }

输出为：

You will have PT30M between the movies

Duration 对象打印有点滑稽。格式为 ISO 8601。对于您的用户，您将希望格式化得更漂亮，例如 You will have 30 minutes between the movies。搜索 and/or 如何使用底部的链接。在 WWW 上的各个地方都有描述。

链接

Oracle tutorial: Date Time 解释如何使用 java.time.
Wikipedia article: ISO 8601
关于如何格式化 a Duration 的问题和答案：
- Convert seconds value to hours minutes seconds? — My answer
- How to format a duration in java? (e.g format H:MM:SS) — Answer by lauhub

有没有办法在Java中做24小时格式和60分钟格式？

Is there a way to do 24-hour format and 60-minute format in Java?

java

time

if-statement

java.time

链接