下面是输入和输出，以及我所做的代码片段。我们可以编写一个函数来动态获取 id 并创建输出吗？

Question

输入

{"records" : {
    "a1s1X000000YKalQAG" : {
      "apiName" : "SP_Attribute__c",
      "childRelationships" : { },
      "eTag" : "c9439586feca3af5df2121fe7cfbc4ca",
      "fields" : {
        "Name" : {
          "displayValue" : null,
          "value" : "EuipmentRecord2"
        },
        "SP_Internal_Number__c" : {
          "displayValue" : null,
          "value" : "a"
        },
        "SP_Type__c" : {
          "displayValue" : null,
          "value" : "B"
        },
        "SP_Unit__c" : {
          "displayValue" : null,
          "value" : "C"
        },
        "SP_Value__c" : {
          "displayValue" : null,
          "value" : "D"
        }
      },
      "id" : "a1s1X000000YKalQAG",
      "lastModifiedById" : "0051X0000090wZKQAY",
      "lastModifiedDate" : "2021-11-19T10:18:57.000Z",
      "recordTypeId" : "012000000000000AAA",
      "recordTypeInfo" : null,
      "systemModstamp" : "2021-11-19T10:18:57.000Z",
      "weakEtag" : 1637317137000
    },
    "a1s1X000000YIWLQA4" : {
      "apiName" : "SP_Attribute__c",
      "childRelationships" : { },
      "eTag" : "fd1b7751ece0fee39101ca1e0bbb80b3",
      "fields" : {
        "Name" : {
          "displayValue" : null,
          "value" : "EuipmentRecord1"
        },
        "SP_Internal_Number__c" : {
          "displayValue" : null,
          "value" : null
        },
        "SP_Type__c" : {
          "displayValue" : null,
          "value" : null
        },
        "SP_Unit__c" : {
          "displayValue" : null,
          "value" : null
        },
        "SP_Value__c" : {
          "displayValue" : null,
          "value" : null
        }
      },
      "id" : "a1s1X000000YIWLQA4",
      "lastModifiedById" : "0051X0000090wZKQAY",
      "lastModifiedDate" : "2021-11-09T12:36:22.000Z",
      "recordTypeId" : "012000000000000AAA",
      "recordTypeInfo" : null,
      "systemModstamp" : "2021-11-09T12:36:22.000Z",
      "weakEtag" : 1636461382000
    }
  }}

Dataweave

%dw 2.0
output application/json
var ids = ["a1s1X000000YKalQAG", "a1s1X000000YIWLQA4"]
var a = [payload.records."$(ids[0])".fields pluck (($$): $.value)]++ [(payload.records."$(ids[1])".fields pluck (($$): $.value))]
---
a

输出

[
  [
    {
      "Name": "EuipmentRecord2"
    },
    {
      "SP_Internal_Number__c": "a"
    },
    {
      "SP_Type__c": "B"
    },
    {
      "SP_Unit__c": "C"
    },
    {
      "SP_Value__c": "D"
    }
  ],
  [
    {
      "Name": "EuipmentRecord1"
    },
    {
      "SP_Internal_Number__c": null
    },
    {
      "SP_Type__c": null
    },
    {
      "SP_Unit__c": null
    },
    {
      "SP_Value__c": null
    }
  ]
]

保持输出相同，挑战在于编写一个动态获取这些 ID 并创建输出的函数，因此在此示例中有两个 ID -“a1s1X000000YKalQAG”、“a1s1X000000YIWLQA4”，因此变量“a”有两个数组要连接，[payload.records."$(ids[0])".fields pluck (($$): $.value)]++ [(payload.records."$( ids[1])".fields 采摘 (($$): $.value))].

我们可以写一个函数让整个事情动态化吗？所以如果有 n 个 id，-> id1 ++ id2 ++ id3... id(n) ?

Answer 1

ID 似乎是记录值的键，因此您可以只使用 namesOf() 函数将键提取为字符串列表，以避免在脚本中对其进行硬编码：

%dw 2.0 
output application/json
fun convertById(data) = 
    payload.records 
        pluck ($.fields)
        map ($ pluck (($$): $.value) )
---
convertById(payload)

更新：封装成一个函数。 Update2：让它对任意数量的 id 都是动态的。

下面是输入和输出，以及我所做的代码片段。我们可以编写一个函数来动态获取 id 并创建输出吗？

Below is the input and output, along with a code snippet of what i've done. Can we write a function to take ids dynamically and create the output?

dataweave

mule4