Django - TypeError: object of type 'method' has no len()
Django - TypeError: object of type 'method' has no len()
我正在尝试使用一些在线代码将分页器添加到我的网站,但出现此错误
return长度(self.object_list)
类型错误:'method' 类型的对象没有 len()
Views.py
def sample(request):
WAllPAPER_PER_PAGE = 2
wallpapers = Wallpaper.objects.all
page = request.GET.get('page', 1)
wallpaper_paginator = Paginator(wallpapers, WAllPAPER_PER_PAGE)
try:
wallpapers = wallpaper_paginator.page(page)
except EmptyPage:
wallpapers = wallpaper_paginator.page(wallpaper_paginator.num_pages)
except:
wallpapers = wallpaper_paginator.page(WAllPAPER_PER_PAGE)
context = {"wallpapers": wallpapers, 'page_obj': wallpapers, 'is_paginated': True, 'paginator': wallpaper_paginator}
return render(request, "Wallpaper/sample.html", context )
Models.py
class Wallpaper(models.Model):
name = models.CharField(max_length=100, null=True)
size = models.CharField(max_length=50, null=True)
pub_date = models.DateField('date published', null=True)
resolution = models.CharField(max_length=100, null=True)
category = models.ManyToManyField(Category)
tags = models.ManyToManyField(Tags)
Device_Choices = [
('PC', 'pc'),
('mobile', 'mobile')
]
Devices = models.CharField(max_length=20,choices=Device_Choices, default= 'PC')
image = models.ImageField(upload_to='Wallpaper/Images/', default="")
def __str__(self):
return self.name
你需要调用.all()
,否则它是对方法的引用,所以你使用:
# call .all() ↓↓
wallpapers = Wallpaper.objects<strong>.all()</strong>
您需要调用它的原因是因为 Paginator
需要可迭代且具有长度的内容,例如列表或 QuerySet
。
我正在尝试使用一些在线代码将分页器添加到我的网站,但出现此错误 return长度(self.object_list) 类型错误:'method' 类型的对象没有 len()
Views.py
def sample(request):
WAllPAPER_PER_PAGE = 2 wallpapers = Wallpaper.objects.all page = request.GET.get('page', 1) wallpaper_paginator = Paginator(wallpapers, WAllPAPER_PER_PAGE) try: wallpapers = wallpaper_paginator.page(page) except EmptyPage: wallpapers = wallpaper_paginator.page(wallpaper_paginator.num_pages) except: wallpapers = wallpaper_paginator.page(WAllPAPER_PER_PAGE) context = {"wallpapers": wallpapers, 'page_obj': wallpapers, 'is_paginated': True, 'paginator': wallpaper_paginator} return render(request, "Wallpaper/sample.html", context )
Models.py
class Wallpaper(models.Model):
name = models.CharField(max_length=100, null=True)
size = models.CharField(max_length=50, null=True)
pub_date = models.DateField('date published', null=True)
resolution = models.CharField(max_length=100, null=True)
category = models.ManyToManyField(Category)
tags = models.ManyToManyField(Tags)
Device_Choices = [
('PC', 'pc'),
('mobile', 'mobile')
]
Devices = models.CharField(max_length=20,choices=Device_Choices, default= 'PC')
image = models.ImageField(upload_to='Wallpaper/Images/', default="")
def __str__(self):
return self.name
你需要调用.all()
,否则它是对方法的引用,所以你使用:
# call .all() ↓↓
wallpapers = Wallpaper.objects<strong>.all()</strong>
您需要调用它的原因是因为 Paginator
需要可迭代且具有长度的内容,例如列表或 QuerySet
。