将 XML 解析为 JSON Elixir

Question

任何人都知道如何将 xml 转换为 json。我试过 Sweetyxml 但它没有将 xml 转换成 json.

使用这个要点 https://gist.github.com/spint/40717d4e6912d8cea929 阅读 json

{:ok, xmldoc} = File.read(Path.expand("/Users/sohaibanwar/Desktop/unconfirmed_order.xml"))

{doc, []} = xmldoc |> to_charlist() |> :xmerl_scan.string() 
After parsing (in screenshot), but not getting right answer

我正在使用的 YML 文件

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<order>
    <orderId>35267684</orderId>
    <orderToken>fa74171d-f54a-4e76-bcf2-2dd284ac6450</orderToken>
    <brokerTicketId>169855177</brokerTicketId>
    <section>SEC1</section>
    <row>N</row>
    <seats/>
    <notes>Limited view. Please note that you will need to use an iOS or Android mobile device to gain entry to your event.</notes>
    <quantity>2</quantity>
    <cost>324.00</cost>
    <event>Dave Matthews Band (Rescheduled from 7/17/2020, 7/16/2021)</event>
    <eventDate>2021-08-20 19:30:00</eventDate>
    <orderDate>2021-06-18 05:43:13</orderDate>
    <expectedShipDate>2021-06-18 00:00:00</expectedShipDate>
    <venue>Xfinity Center - MA - Mansfield, MA</venue>
    <status>UNCONFIRMED</status>
    <purchaseOrderId>35088971</purchaseOrderId>
    <electronicDelivery>false</electronicDelivery>
    <passThrough></passThrough>
    <listingId>3359267717</listingId>
    <productionId>3412459</productionId>
    <eventId>218</eventId>
    <zone>false</zone>
    <barCodesRequired>false</barCodesRequired>
    <transferViaURL>true</transferViaURL>
    <instantTransfer>false</instantTransfer>
    <instantFlashSeats>false</instantFlashSeats>
</order>

要求的结果 您可以在此处粘贴 XML 以获得所需的答案

{
  "order": {
    "orderId": 35267684,
    "orderToken": "fa74171d-f54a-4e76-bcf2-2dd284ac6450",
    "brokerTicketId": 169855177,
    "section": "SEC1",
    "row": "N",
    "seats": "",
    "notes": "Limited view. Please note that you will need to use an iOS or Android mobile device to gain entry to your event.",
    "quantity": 2,
    "cost": 324,
    "event": "Dave Matthews Band (Rescheduled from 7/17/2020, 7/16/2021)",
    "eventDate": "2021-08-20 19:30:00",
    "orderDate": "2021-06-18 05:43:13",
    "expectedShipDate": "2021-06-18 00:00:00",
    "venue": "Xfinity Center - MA - Mansfield, MA",
    "status": "UNCONFIRMED",
    "purchaseOrderId": 35088971,
    "electronicDelivery": false,
    "passThrough": "",
    "listingId": 3359267717,
    "productionId": 3412459,
    "eventId": 218,
    "zone": false,
    "barCodesRequired": false,
    "transferViaURL": true,
    "instantTransfer": false,
    "instantFlashSeats": false
  }
}

Answer 1

好吧，如果您的问题是 How to convert xml to json in Elixir，答案很简单：使用您选择的 https://github.com/homanchou/elixir-xml-to-map 和 JSON 编码器：

def xml2json(path) do
  File.read!(path)
  |> XmlToMap.naive_map()
  |> Jason.encode!()
end

这个答案的问题在于 XML 与映射不同（您在 XML 中同时具有标签和属性，而在映射或 JSON 中却没有），所以更好的方法是使用 SweetXML（或 :xmerl）并像这里一样使用适当的匹配来做 xmap（代码来自 SweetXML 示例 - https://github.com/kbrw/sweet_xml#examples）：

result = doc |> xmap(
  matchups: [
    ~x"//matchups/matchup"l,
    name: ~x"./name/text()",
    winner: [
      ~x".//team/id[.=ancestor::matchup/@winner-id]/..",
      name: ~x"./name/text()"
    ]
  ],
  last_matchup: [
    ~x"//matchups/matchup[last()]",
    name: ~x"./name/text()",
    winner: [
      ~x".//team/id[.=ancestor::matchup/@winner-id]/..",
      name: ~x"./name/text()"
    ]
  ]
)
assert result == %{
  matchups: [
    %{name: 'Match One', winner: %{name: 'Team One'}},
    %{name: 'Match Two', winner: %{name: 'Team Two'}},
    %{name: 'Match Three', winner: %{name: 'Team One'}}
  ],
  last_matchup: %{name: 'Match Three', winner: %{name: 'Team One'}}
}

另一种选择是使用 https://github.com/willemdj/erlsom 并手动遍历它从 simple_form 调用发出的元组树。请注意，无论如何您都必须处理 XMLNS 和 attr/value 问题。

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