如果使用 OR 或 AND 门，如何表示嵌套？

Question

a=int(input("Enter a"))
b=int(input("Enter b"))
c=int(input("Enter c"))
if(a>b and a>c):
    print("a is greatest")
elif(b>a and b>c):
    print("b is greatest")
else:
    print("c is greatest")

这是我的代码，用于查找 3 个数字之间的最大数。

我的课本上写了不同的代码，我想把它转换成我的代码类型。

课本上写的代码如下-:

num1=int(input("Enter num1"))
num2=int(input("Enter num2"))
num3=int(input("Enter num3"))
if(num1>num2):
    if(num1>num3):
        print(num1,"is greater than",num2,"and",num3)
    else:
        print(num3, "is greater than", num1, "and", num2)
elif(num2>num3):
    print(num2,"is greater than",num1,"and",num3)
else:
    print("The three numbers are equal")

我想在if条件和elif条件中将这个if语句转换成布尔表达式，我该怎么做？

Answer 1

这是一个动态的方法。它有点复杂，但效果很好。

如果你仔细阅读它，那么你就会明白它。

items = [int(input("Enter a: ")), int(input("Enter b: ")), int(input("Enter c: "))]
highest = items[0]
letter = "A"
for index, item in enumerate(items):
    if item > highest:
        highest = item
        letter = chr(ord("A")+index)

print("{letter} has the highest value of {highest}".format(letter=letter, highest=highest))

Answer 2

if (num1>num2) and (num1>num3):
    print(num1,"is greater than",num2,"and",num3)
elif (num3>num1) and (num3>num2):
    print(num3, "is greater than", num1, "and", num2)
elif (num2>num3) and (num2>num1):
    print(num2,"is greater than",num1,"and",num3)
else:
    print("The three numbers are equal")

您可以随时使用 max(num1,num2,num3) 功能，但我猜您不想要那个。

编辑：

在您书中的示例中，在外部 if 和其嵌套的 if-else 之间有一个隐式的 AND 运算符。所以

if(num1>num2):
    if(num1>num3):
        print(num1,"is greater than",num2,"and",num3)
    else:
        print(num3, "is greater than", num1, "and", num2)

实际上等同于

if(num1>num2) and (num1>num3):
    print(num1,"is greater than",num2,"and",num3)
if(num1>num2) and (num1<=num3):
    print(num3, "is greater than", num1, "and", num2)

同样，

elif(num2>num3):
    print(num2,"is greater than",num1,"and",num3)

相当于

if(num1<=num2) and (num2>num3):
    print(num2,"is greater than",num1,"and",num3)

如果使用 OR 或 AND 门，如何表示嵌套？

How to represent nested if using OR or AND gates?

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