TypeError: float() argument must be a string or a number, not 'list' and ValueError: setting an array element with a sequence

Question

Sample = [{'id': 1, 'Jan': 150, 'Feb': 200, 'Mar': [[.332, .326], [.058, .138]]},
 {'id': 2,  'Jan': 200, 'Feb': 210, 'Mar': [[.234, .246], [.234, .395]]},
 {'id': 3,  'Jan': 50,  'Feb': 90,  'Mar': [[.084, .23], [.745, .923]]}]
df = pd.DataFrame(Sample)
df

df=df.assign(New=df[['Feb', 'Jan']].values.tolist())

这里我尝试从数据帧中找到 K 个最近的邻居

from sklearn.neighbors import NearestNeighbors

knn = NearestNeighbors(n_neighbors=10, algorithm='auto')
knn.fit(df['New'].to_numpy())

def get_neighbors(id):
    vector = df.loc[id]
    return knn.kneighbors([vector], 10, return_distance=False)

但是 TypeError: float() 参数必须是字符串或数字，而不是 'list' 出现在行 knn.fit(df['New'].to_numpy())

Answer 1

df=df.assign(New=df[['Feb', 'Jan']].values.tolist())

试试这条线

New = df[['Feb', 'Jan']].values.tolist()

TypeError: float() argument must be a string or a number, not 'list' and ValueError: setting an array element with a sequence

TypeError: float() argument must be a string or a number, not 'list' and ValueError: setting an array element with a sequence

python

knn