如何从嵌套数组中删除数组，遍历其余数组。然后循环遍历嵌套数组的 1 个值，全部在 vanilla js 中

Question

let linkMatrix = [
    [0,0,1,0],
    [1,0,0,1],
    [1,1,0,1],
    [0,1,0,0]
];


let newMatrix = [];

function linkToPage(){

    for(let j = 0; j < linkMatrix.length; j--){
        newMatrix = linkMatrix.splice(linkMatrix[j], 1);
        console.log(linkMatrix + " Here is linkMatrix");

        
            for(let i = 0; i < newMatrix.length; i++){
                newMatrix.splice(newMatrix[i]);
                console.log(newMatrix + " Here is newMatrix");
            }
        
    }

**我想做的是循环遍历第一个数组但删除第一个数组，因为我不需要循环遍历它，然后循环遍历其余数组，但唯一的值我需要的是已删除数组索引中的值，以便更好地理解：如果我们有一个像这样的数组 arr = [[0,1],[1,0],[1,1]] 然后删除 [ 0,1] 并且因为它是 arr[0]，我想遍历其他数组的 0 索引所以我会得到 1 和 1，然后返回到原始数组删除 arr[1] 并循环遍历 arr [0],arr[2] 到数组的 1 索引，所以我会得到 [1,1] **

**Yeah, so the wanted result from my link matrix would be: 
    [0,0,1,0] = 2 
    [1,0,0,1] = 2
    [1,1,0,1] = 1
    [0,1,0,0] = 2
because there is 2 other arrys pointing to the first array, the same for the second and fourth, but there is only one array pointing to the third array
    **

Answer 1

您可以添加列的值。

const
    getColSum = matrix => matrix.reduce((r, a) => a.map((v, i) => (r[i] || 0) + v), []);

console.log(...getColSum([[0, 0, 1, 0], [1, 0, 0, 1], [1, 1, 0, 1], [0, 1, 0, 0]]));
console.log(...getColSum([[0, 0, 0], [1, 0, 0], [1, 1, 0]]));

没有（几乎）数组方法的版本。

function getColSum (matrix) {
    const result = Array(matrix[0].length).fill(0);

    for (const row of matrix) {
        for (let i = 0; i < row.length; i++) result[i] += row[i];
    }

    return result;
}

console.log(...getColSum([[0, 0, 1, 0], [1, 0, 0, 1], [1, 1, 0, 1], [0, 1, 0, 0]]));
console.log(...getColSum([[0, 0, 0], [1, 0, 0], [1, 1, 0]]));

如何从嵌套数组中删除数组，遍历其余数组。然后循环遍历嵌套数组的 1 个值，全部在 vanilla js 中

How to remove an array from a nested array, loop throug the rest of the arrays. And then loop throug 1 value of the nested arrays, all in vanilla js

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