我的计时器脚本中的数学是错误的... Lua Minecraft
Maths in my timer script is wrong... Lua Minecraft
idk 出了什么问题,但是它在保存值时将其写入文件。如果您需要更多信息或有任何疑问,请问我!感谢您的宝贵时间,希望您能找到解决方案! SebyGHG 我的不和谐:S̸̽̚e̵̓̓b̸̿̕y̴͆͐#4638 os.time() 给你一个数字的值。感谢您的关注!
文件中的示例时间:1638185640
游戏中显示的时间示例:
name = "Timer"
description = "Just a normal Timer."
positionX = 0
positionY = 0
sizeX = 24
sizeY = 10
scale = 1
START_STOP_KEY = 0x55 --or 'U'
RESET_KEY = 0x4A --or 'J'
--
--[[
Timer Module Script by SebyGHG original script by Onix64(Stopwatch)
if you wish to change the key you can take the key code from here
https://docs.microsoft.com/en-us/windows/win32/inputdev/virtual-key-codes
]] -------------script-code-------------
state = 1
stopTime = 0
startTime = 0
f = io.input("timesave.txt")
result = f :read()
f :close()
stopTime = result
state = 2
function keyboard(key, isDown)
if (isDown == true) then
if (key == RESET_KEY) then
state = 0
elseif (key == START_STOP_KEY) then
if (state == 0) then
state = 1
startTime = os.time()
elseif (state == 1) then
state = 2
io.output("timesave.txt")
timesave= (io.open("timesave.txt","w"))
io.write(stopTime)
io.close(timesave)
stopTime = os.time() -stopTime
elseif (state == 2) then
state = 1
startTime =startTime + os.time() - stopTime
end
end
end
end
TimerText = "00:00"
TextColor = {r = 30, g = 255, b = 30, a = 255}
function doubleDigit(number)
if (number < 10) then
return "0" .. math.floor(number)
else
return math.floor(number)
end
end
function timeText(time)
local result = ""
local days = 0
while (time > 86399) do
days = days + 1
time = time - 86400
end
local hours = 0
while (time > 3599) do
hours = hours + 1
time = time - 3600
end
local minutes = 0
while (time > 59) do
minutes = minutes + 1
time = time - 60
end
if (days == 0) then
if (hours == 0) then
return doubleDigit(minutes) .. ":" .. doubleDigit(time)
else
return math.floor(hours) .. " : " .. doubleDigit(minutes) .. ":" .. doubleDigit(time)
end
else
return math.floor(days) ..
" : " .. doubleDigit(hours) .. " : " .. doubleDigit(minutes) .. ":" .. doubleDigit(time)
end
end
function update()
if (state == 0) then
TextColor = {r = 255, g = 0, b = 0, a = 255}
TimerText = "00:00"
elseif (state == 1) then
TimerText = timeText(os.time() - startTime)
TextColor = {r = 0, g = 255, b = 255, a = 255}
elseif (state == 2) then
TimerText = timeText(stopTime - startTime)
TextColor = {r = 255, g = 255, b = 0, a = 255}
end
end
function render()
local font = gui.font()
local tw = font.width(TimerText)
gfx.color(0, 0, 0, 0)
gfx.rect(0, 0, tw + 4, 10)
gfx.color(TextColor.r, TextColor.g, TextColor.b, TextColor.a)
gfx.text(2, 1, TimerText)
end
您似乎正在将 Unix 时间戳保存到您的文件中,您可以尝试使用在线时间转换器使其可读 (https://time.is/Unix_time_converter)
除此之外,请花一些时间阅读此 lua 页面上的 os.time() 实施细节:https://www.lua.org/pil/22.1.html
The time function, when called without arguments, returns the current date and time, coded as a number. (In most systems, that number is the number of seconds since some epoch.)
如果你想要某个动作之间的时间,保存初始时间戳并在动作结束时比较它。 lua 使用 os.difftime() 原生支持此功能。 (http://www.lua.org/manual/5.3/manual.html#pdf-os.difftime)
idk 出了什么问题,但是它在保存值时将其写入文件。如果您需要更多信息或有任何疑问,请问我!感谢您的宝贵时间,希望您能找到解决方案! SebyGHG 我的不和谐:S̸̽̚e̵̓̓b̸̿̕y̴͆͐#4638 os.time() 给你一个数字的值。感谢您的关注!
文件中的示例时间:1638185640
游戏中显示的时间示例:
name = "Timer"
description = "Just a normal Timer."
positionX = 0
positionY = 0
sizeX = 24
sizeY = 10
scale = 1
START_STOP_KEY = 0x55 --or 'U'
RESET_KEY = 0x4A --or 'J'
--
--[[
Timer Module Script by SebyGHG original script by Onix64(Stopwatch)
if you wish to change the key you can take the key code from here
https://docs.microsoft.com/en-us/windows/win32/inputdev/virtual-key-codes
]] -------------script-code-------------
state = 1
stopTime = 0
startTime = 0
f = io.input("timesave.txt")
result = f :read()
f :close()
stopTime = result
state = 2
function keyboard(key, isDown)
if (isDown == true) then
if (key == RESET_KEY) then
state = 0
elseif (key == START_STOP_KEY) then
if (state == 0) then
state = 1
startTime = os.time()
elseif (state == 1) then
state = 2
io.output("timesave.txt")
timesave= (io.open("timesave.txt","w"))
io.write(stopTime)
io.close(timesave)
stopTime = os.time() -stopTime
elseif (state == 2) then
state = 1
startTime =startTime + os.time() - stopTime
end
end
end
end
TimerText = "00:00"
TextColor = {r = 30, g = 255, b = 30, a = 255}
function doubleDigit(number)
if (number < 10) then
return "0" .. math.floor(number)
else
return math.floor(number)
end
end
function timeText(time)
local result = ""
local days = 0
while (time > 86399) do
days = days + 1
time = time - 86400
end
local hours = 0
while (time > 3599) do
hours = hours + 1
time = time - 3600
end
local minutes = 0
while (time > 59) do
minutes = minutes + 1
time = time - 60
end
if (days == 0) then
if (hours == 0) then
return doubleDigit(minutes) .. ":" .. doubleDigit(time)
else
return math.floor(hours) .. " : " .. doubleDigit(minutes) .. ":" .. doubleDigit(time)
end
else
return math.floor(days) ..
" : " .. doubleDigit(hours) .. " : " .. doubleDigit(minutes) .. ":" .. doubleDigit(time)
end
end
function update()
if (state == 0) then
TextColor = {r = 255, g = 0, b = 0, a = 255}
TimerText = "00:00"
elseif (state == 1) then
TimerText = timeText(os.time() - startTime)
TextColor = {r = 0, g = 255, b = 255, a = 255}
elseif (state == 2) then
TimerText = timeText(stopTime - startTime)
TextColor = {r = 255, g = 255, b = 0, a = 255}
end
end
function render()
local font = gui.font()
local tw = font.width(TimerText)
gfx.color(0, 0, 0, 0)
gfx.rect(0, 0, tw + 4, 10)
gfx.color(TextColor.r, TextColor.g, TextColor.b, TextColor.a)
gfx.text(2, 1, TimerText)
end
您似乎正在将 Unix 时间戳保存到您的文件中,您可以尝试使用在线时间转换器使其可读 (https://time.is/Unix_time_converter)
除此之外,请花一些时间阅读此 lua 页面上的 os.time() 实施细节:https://www.lua.org/pil/22.1.html
The time function, when called without arguments, returns the current date and time, coded as a number. (In most systems, that number is the number of seconds since some epoch.)
如果你想要某个动作之间的时间,保存初始时间戳并在动作结束时比较它。 lua 使用 os.difftime() 原生支持此功能。 (http://www.lua.org/manual/5.3/manual.html#pdf-os.difftime)