SQL 使用jsonb_to_recordset 函数时出现错误42P01

Question

我正在尝试使用 jsonb_to_recordset 函数显示 jsonb 列的内容：

SELECT id, city
FROM jsonb_to_recordset("sometable".data) AS t(id int4, city varchar)

但是得到如下错误

SQL Error [42P01]: ERROR: missing FROM-clause entry for table "sometable"

当我手动替换值时，该函数本身起作用。不明白是什么问题。

Answer 1

写成 FROM...JOIN:

-- inner join
SELECT t.id, t.city
FROM sometable
CROSS JOIN LATERAL jsonb_to_recordset(sometable.data) AS t(id int4, city varchar)

-- outer join, include rows where jsonb is null
SELECT t.id, t.city
FROM sometable
LEFT JOIN LATERAL jsonb_to_recordset(sometable.data) AS t(id int4, city varchar) ON true

SQL 使用jsonb_to_recordset 函数时出现错误42P01

SQL error 42P01 when using jsonb_to_recordset function

sql

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