Oracle 动态查找每个 table 的行数和列数
Oracle dynamic find number of rows and columns per table
我有以下查询,其中 returns 模式中每个 table 的行数。
这也可以修改为 RETURN 每 table 的列数吗?
CREATE table stats (
table_name VARCHAR2(128),
num_rows NUMBER,
num_cols NUMBER
);
/
DECLARE
val integer;
BEGIN
for i in (SELECT table_name FROM all_tables WHERE owner = 'Schema')
LOOP
EXECUTE IMMEDIATE 'SELECT count(*) from ' || i.table_name INTO val;
INSERT INTO stats VALUES (i.table_name,val);
END LOOP;
END;
/
您可以使用 ALL_TAB_COLS
字典 table:
DECLARE
val integer;
BEGIN
FOR i IN (
SELECT table_name,
COUNT(*) AS num_cols
FROM all_tab_cols
WHERE owner = 'Schema'
GROUP BY table_name
)
LOOP
EXECUTE IMMEDIATE 'SELECT count(*) from ' || i.table_name INTO val;
INSERT INTO stats VALUES (i.table_name,val, i.num_cols);
END LOOP;
END;
/
db<>fiddle here
我有以下查询,其中 returns 模式中每个 table 的行数。
这也可以修改为 RETURN 每 table 的列数吗?
CREATE table stats (
table_name VARCHAR2(128),
num_rows NUMBER,
num_cols NUMBER
);
/
DECLARE
val integer;
BEGIN
for i in (SELECT table_name FROM all_tables WHERE owner = 'Schema')
LOOP
EXECUTE IMMEDIATE 'SELECT count(*) from ' || i.table_name INTO val;
INSERT INTO stats VALUES (i.table_name,val);
END LOOP;
END;
/
您可以使用 ALL_TAB_COLS
字典 table:
DECLARE
val integer;
BEGIN
FOR i IN (
SELECT table_name,
COUNT(*) AS num_cols
FROM all_tab_cols
WHERE owner = 'Schema'
GROUP BY table_name
)
LOOP
EXECUTE IMMEDIATE 'SELECT count(*) from ' || i.table_name INTO val;
INSERT INTO stats VALUES (i.table_name,val, i.num_cols);
END LOOP;
END;
/
db<>fiddle here