将 Array 对象拆分为夹头

Question

我在 JS 中有这个数组

initialArray = [A,B,C,C,D,E,F,F,G,K]

我想分成：

chucks = [[A,B,C], [C,D,E,F], [F,G,K]]

重复项是分隔符，例如 'C' 或 'F'

如何在 ES6 中进行拆分？

Answer 1

您可以减少数组并添加值或新数组，具体取决于最后一个值。

const
    array = ['A','B','C','C','D','E','F','F','G','K'],
    result = array.reduce((r, v, i, { [i - 1]: last }) => {
        if (v === last) r.push([]);
        r[r.length - 1].push(v);
        return r;
    }, [[]]);

console.log(result);

Answer 2

已编辑：现在基于克隆

const initialArray = ["A","B","C","C","D","E","F","F","G","K"];
const chunks = [];
let smallChunk = [];

let index = 0;

while (index < initialArray.length){
  smallChunk.push(initialArray[index]);
  
  if (initialArray[index+1] == initialArray[index]){
    chunks.push(smallChunk);
    smallChunk = [];
  }
  
  index++;
}

chunks.push(smallChunk);
console.log(chunks);

Answer 3

使用单个 for 循环并将当前块保存在要推送到的变量中的相当直接的解决方案。

const initialArray = ['A', 'A', 'B', 'C', 'C', 'D', 'E', 'F', 'F', 'G', 'K', 'K'];

const chunk_at_duplicate = (arr) => {
  let chunk = [], res = [chunk];

  for (let i = 0; i < arr.length; i++) {
    if (arr[i] === arr[i - 1]) {
      res.push(chunk = []);
    }

    chunk.push(arr[i]);
  }

  return res;
};

console.log(chunk_at_duplicate(initialArray));

Answer 4

您可以将 for ... of 与 initialArray.entries() 一起使用，如下所示：

const initialArray = ["A","B","C","C","D","E","F","F","G","K"];

const chunks = [];
let start = 0
for(const [i,v] of initialArray.entries()) {
    if(i > 0 && v === initialArray[i-1]) {
        chunks.push( initialArray.slice(start,i) );
        start = i;
    } else if( i === initialArray.length - 1 ) {
        chunks.push( initialArray.slice(start) );
    }
}

console.log( chunks );

将 Array 对象拆分为夹头

Split Array object into chucks

javascript

arrays

split