如何在使用 middy 时单元测试是否调用了处理函数
how to unit test if handler function is called when using middy
我在middy中使用一个http请求函数作为处理函数,然后在发起http请求之前使用ssm中间件获取一些ssm参数。
像这样:
const makeThirdPartyServiceRequest = middy(async ({ params }) => {
logger.info(`SENDING Request to ${endpoint} API`)
const url = `https://someurltoathirdpartyservice`
const options = {
method: 'POST',
body: params
}
return helpers.makeRequest(url, options)
})
makeThirdPartyServiceRequest.use(ssm(......))
然而,在我开玩笑的单元测试中,我试图模拟 makeThirdPartyServiceRequest 并明确表示它应该解析为一个值:
jest.mock('../src/thirdPartyService', () => ({
__esModule: true,
default: {
...(jest.requireActual('../src/thirdPartyService') as { default: {} }).default,
makeThirdPartyServiceRequest: jest.fn()
}
}))
export {}
import thirdPartyService from '../src/thirdPartyService'
然后在测试中我说:
describe('makeThirdPartyServiceRequest()', () => {
it('should makeThirdPartyServiceRequest', async () => {
// Given
// })
const mockedThirdPartyServiceRequest = mocked(thirdPartyService.makeThirdPartyServiceRequest).mockResolvedValue({})
// When
const result = await thirdPartyService.makeThirdPartyServiceRequest(something)
// Then
expect(mockedThirdPartyServiceRequest).toHaveBeenCalledTimes(1)
expect(mockedThirdPartyServiceRequest.mock.calls[0][0].params.toString()).toBe(expectedParams)
})
})
但是由于某种原因,middy 中间件仍在被调用,我显然不希望这样,我试图模拟掉...我做错了什么?
你需要 mock middy
,让它变成一个无用的函数。该函数将函数配方作为参数,并且 return 该参数。
import thirdPartyService from '../src/thirdPartyService'
jest.mock('@middy/core', () => {
return (handler) => {
return {
use: jest.fn().mockReturnValue(handler), // ...use(ssm()) will return handler function
}
}
})
describe('thirdPartyService()', () => {
beforeEach(() => {
jest.spyOn(helpers, 'makeRequest') // spy on helpers unit
})
describe('makeThirdPartyServiceRequest', () => {
it('should make a request with correct parameters', async () => {
// Given
const url = `https://someurltoathirdpartyservice`
const params = 'any params'
const apiResponse = 'any response'
mocked(helpers.makeRequest).mockResolvedValue(apiResponse)
// When
const actual = await thirdPartyService.makeThirdPartyServiceRequest(params)
// Then
expect(actual).toBe(apiResponse)
expect(helpers.makeRequest).toHaveBeenCalledWith(
url,
{
method: 'POST',
body: params
}
)
})
})
})
hoangdv 的回答也是有效的,但我也会回答我是如何继续的。
如果你完全想模拟 middy,你可以像下面这样模拟:
jest.mock('@middy/core', () => {
return (handler) => {
return {
use: jest.fn().mockImplementation(() => {
// ...use(ssm()) will return handler function
return {
before: jest.fn().mockReturnValue(handler)
}
})
}
}
})
但是,如果您不想完全模拟 middy,您可以模拟之前调用的 middy/util 中的异步 getInternal 函数,如下所示:
jest.doMock('@middy/util', () => ({
...(jest.requireActual('@middy/util') as {}),
getInternal: jest.fn()
}))
import { getInternal } from '@middy/util'
然后在测试
describe('thirdPartyService()', () => {
beforeEach(() => {
jest.spyOn(helpers, 'makeRequest') // spy on helpers unit
})
describe('makeThirdPartyServiceRequest', () => {
it('should make a request with correct parameters', async () => {
// Given
const url = `https://someurltoathirdpartyservice`
const params = 'any params'
const apiResponse = 'any response'
mocked(getInternal).mockResolvedValue({
twilioSecrets: { accountSid: 'someSID', serviceId:
'someServiceID', token: 'someToken' }
})
mocked(helpers.makeRequest).mockResolvedValue(apiResponse)
// When
const actual = await thirdPartyService.makeThirdPartyServiceRequest(params)
// Then
expect(actual).toBe(apiResponse)
expect(helpers.makeRequest).toHaveBeenCalledWith(
url,
{
method: 'POST',
body: params
}
)
})
})
})
这将模拟 middy 的异步部分。
我在middy中使用一个http请求函数作为处理函数,然后在发起http请求之前使用ssm中间件获取一些ssm参数。 像这样:
const makeThirdPartyServiceRequest = middy(async ({ params }) => {
logger.info(`SENDING Request to ${endpoint} API`)
const url = `https://someurltoathirdpartyservice`
const options = {
method: 'POST',
body: params
}
return helpers.makeRequest(url, options)
})
makeThirdPartyServiceRequest.use(ssm(......))
然而,在我开玩笑的单元测试中,我试图模拟 makeThirdPartyServiceRequest 并明确表示它应该解析为一个值:
jest.mock('../src/thirdPartyService', () => ({
__esModule: true,
default: {
...(jest.requireActual('../src/thirdPartyService') as { default: {} }).default,
makeThirdPartyServiceRequest: jest.fn()
}
}))
export {}
import thirdPartyService from '../src/thirdPartyService'
然后在测试中我说:
describe('makeThirdPartyServiceRequest()', () => {
it('should makeThirdPartyServiceRequest', async () => {
// Given
// })
const mockedThirdPartyServiceRequest = mocked(thirdPartyService.makeThirdPartyServiceRequest).mockResolvedValue({})
// When
const result = await thirdPartyService.makeThirdPartyServiceRequest(something)
// Then
expect(mockedThirdPartyServiceRequest).toHaveBeenCalledTimes(1)
expect(mockedThirdPartyServiceRequest.mock.calls[0][0].params.toString()).toBe(expectedParams)
})
})
但是由于某种原因,middy 中间件仍在被调用,我显然不希望这样,我试图模拟掉...我做错了什么?
你需要 mock middy
,让它变成一个无用的函数。该函数将函数配方作为参数,并且 return 该参数。
import thirdPartyService from '../src/thirdPartyService'
jest.mock('@middy/core', () => {
return (handler) => {
return {
use: jest.fn().mockReturnValue(handler), // ...use(ssm()) will return handler function
}
}
})
describe('thirdPartyService()', () => {
beforeEach(() => {
jest.spyOn(helpers, 'makeRequest') // spy on helpers unit
})
describe('makeThirdPartyServiceRequest', () => {
it('should make a request with correct parameters', async () => {
// Given
const url = `https://someurltoathirdpartyservice`
const params = 'any params'
const apiResponse = 'any response'
mocked(helpers.makeRequest).mockResolvedValue(apiResponse)
// When
const actual = await thirdPartyService.makeThirdPartyServiceRequest(params)
// Then
expect(actual).toBe(apiResponse)
expect(helpers.makeRequest).toHaveBeenCalledWith(
url,
{
method: 'POST',
body: params
}
)
})
})
})
hoangdv 的回答也是有效的,但我也会回答我是如何继续的。
如果你完全想模拟 middy,你可以像下面这样模拟:
jest.mock('@middy/core', () => {
return (handler) => {
return {
use: jest.fn().mockImplementation(() => {
// ...use(ssm()) will return handler function
return {
before: jest.fn().mockReturnValue(handler)
}
})
}
}
})
但是,如果您不想完全模拟 middy,您可以模拟之前调用的 middy/util 中的异步 getInternal 函数,如下所示:
jest.doMock('@middy/util', () => ({
...(jest.requireActual('@middy/util') as {}),
getInternal: jest.fn()
}))
import { getInternal } from '@middy/util'
然后在测试
describe('thirdPartyService()', () => {
beforeEach(() => {
jest.spyOn(helpers, 'makeRequest') // spy on helpers unit
})
describe('makeThirdPartyServiceRequest', () => {
it('should make a request with correct parameters', async () => {
// Given
const url = `https://someurltoathirdpartyservice`
const params = 'any params'
const apiResponse = 'any response'
mocked(getInternal).mockResolvedValue({
twilioSecrets: { accountSid: 'someSID', serviceId:
'someServiceID', token: 'someToken' }
})
mocked(helpers.makeRequest).mockResolvedValue(apiResponse)
// When
const actual = await thirdPartyService.makeThirdPartyServiceRequest(params)
// Then
expect(actual).toBe(apiResponse)
expect(helpers.makeRequest).toHaveBeenCalledWith(
url,
{
method: 'POST',
body: params
}
)
})
})
})
这将模拟 middy 的异步部分。