如何在 SQL 服务器中使用多列进行数据透视？

Question

我在创建遵循下述架构的枢轴 table 时遇到问题。例如，使用以下 table（此处未显示所有记录）：

Route	Bus_Fare_Payment_Method	Total_Annual_Household_Income
Route 1	10-Ride Pass	K To K
Route 1	10-Ride Pass	K To K
Route 1	10-Ride Pass	K To K
Route 1	10-Ride Pass	K Or More
Route 1	Regular Cash Fare	Under K
Route 1	Regular Cash Fare	Under K
Route 1	Regular Cash Fare	Under K
Route 1	Regular Cash Fare	Under K
Route 1	Regular Cash Fare	Under K
Route 1	Regular Cash Fare	Under K
Route 1	Regular Cash Fare	Under K
Route 1	Regular Cash Fare	Under K
Route 10	10-Ride Pass	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 10	31-Day Adult	K To K
Route 101	All Day Pass Reduced	Under K
Route 101	Other	Under K
Route 101	Reduced Fare	K To K
Route 101	Reduced Fare	K To K
Route 101	Reduced Fare	K To K
Route 101	Reduced Fare	K To K
Route 101	Reduced Fare	K Or More
Route 101	Reduced Fare	K Or More
Route 101	Reduced Fare	K Or More
Route 101	Reduced Fare	Under K
Route 101	Reduced Fare	Under K
Route 101	Reduced Fare	Under K
Route 101	Regular Cash Fare	K To K
Route 101	Regular Cash Fare	K To K
Route 101	Regular Cash Fare	K To K
Route 101	Regular Cash Fare	K To K

我想制作以下内容table：

Route	Bus_Fare_Payment_Method	K To K	K To K	K To K	K To K	K To K	K To K	K Or More	Under K
Route 1	10-Ride Pass		2		1			1
Route 1	31-Day Adult
Route 1	All Day Pass Reduced
Route 1	Other
Route 1	Reduced Fare
Route 1	Regular Cash Fare								8
Route 10	10-Ride Pass					1
Route 10	31-Day Adult	4	1	4
Route 10	All Day Pass Reduced
Route 10	Other
Route 10	Reduced Fare
Route 10	Regular Cash Fare
Route 101	10-Ride Pass
Route 101	31-Day Adult
Route 101	All Day Pass Reduced								1
Route 101	Other								1
Route 101	Reduced Fare	1			1	1	1	3	3
Route 101	Regular Cash Fare	4

我可以使用下面包含的查询创建以下内容 table，但我缺少需要作为输出一部分的 Route 字段（如上所示）。

SELECT [Bus_Fare_Payment_Method] "Bus Fare Payment Method", [Under k] 'Under k', [K to K] 'K to K',[k to k] 'k to k', [k to k] 'k to k', [k to k] 'k to k', [k to k] 'k to k', [k to k] 'k to k', [k to k] 'k to k', [k or more] 'k or more'
FROM   
(SELECT [Route], [Total_Annual_Household_Income], [Bus_Fare_Payment_Method]  
FROM [BCT_TDP_SURVEY_2018] where [Bus_Fare_Payment_Method] != '' ) p  
PIVOT  
(  
COUNT ([Route])  
FOR [Total_Annual_Household_Income] IN  
( [Under k], [K to K],[k to k], [k to k], [k to k], [k to k], [k to k], [k to k], [k or more] )  
) AS pvt  
ORDER BY pvt.[Bus_Fare_Payment_Method]

Bus_Fare_Payment_Method	K To K	K To K	K To K	K To K	K To K	K To K	K Or More	Under K
10-Ride Pass		2		1	1		1
31-Day Adult	4	1	4
All Day Pass Reduced								1
Other								1
Reduced Fare	1			1	1	1	3	3
Regular Cash Fare	4							8

Answer 1

正如我在评论中提到的，与限制性 PIVOT 运算符相比，使用条件聚合要好得多：

SELECT Route,
       Bus_Fare_Payment_Method,
       COUNT(CASE Total_Annual_Household_Income WHEN 'K To K' THEN 1 END) AS [K To K],
       COUNT(CASE Total_Annual_Household_Income WHEN 'K To K' THEN 1 END) AS [K To K],
       ...
FROM dbo.YourTable
GROUP BY Route,
         Bus_Fare_Payment_Method;

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