将变量附加到循环列表

Question

如果号码不在之前的列表中，我想将“输入号码”附加到“list_of_already_entered_numbers”。因此，您不应该说出相同的数字 2 次。我添加了“打印”以显示列表仍然是空的？即使“附加”应该在每次迭代期间将数字添加到列表中。别介意 10 次迭代。那么如何将数字附加到列表中以便每次迭代更新列表？

def ask_number():
    a = 0
    while a < 10:
        list_of_already_entered_numbers = []
        print("this is the list: " + str(list_of_already_entered_numbers))
        number = int(input("Type a number:"))
        if number in list_of_already_entered_numbers:
            print("the number is already in the list")
        else:
            list_of_already_entered_numbers.append(number)
        a+=1

ask_number()

Answer 1

像这样在循环外声明列表：

def ask_number():
    a = 0
    list_of_already_entered_numbers = []
    while a < 10:
        print("this is the list: " + str(list_of_already_entered_numbers))
        number = int(input("Type a number:"))
        if number in list_of_already_entered_numbers:
            print("the number is already in the list")
        else:
            list_of_already_entered_numbers.append(number)
        a+=1

ask_number()

Answer 2

您可以尝试仅将询问部分分解为它自己的函数。这样可以更轻松地自行尝试，并确保您获得预期的结果：

from typing import List

def enter_number(previous_numbers: List[int]) -> List[int]:
    print("These numbers have been guessed: {previous_numbers}" + str(list_of_already_entered_numbers))
    number = int(input("Type a number:"))
    if number in previous_numbers:
        print("That number has already been entered")
    else:
        previous_numbers.append(number)
    return previous_numbers

def ask():
    previous_numbers = []
    for _ in range(10):
        previous_numbers = enter_number(previous_numbers)

ask()

通过这种方式，您封装了起始状态，并可以确保每次迭代都完全按照您的预期进行。

将变量附加到循环列表

Append variable to list in loop

python

iteration

loops

if-statement

append