字符串替换为数组中的变量

Question

好的，如果我使用代码：

$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array("fruits", "vegetables", "fiber");
$yummy   = array("pizza", "beer", "ice cream");
$newphrase = str_replace($healthy, $yummy, $phrase);

// Provides: You should eat pizza, beer, and ice cream every day

但是，如果我要替换的单词列表是一个变量怎么办。

$sample1 = "fruits, vegetables, fiber";
$sample2 = "pizza, beer, ice cream";
$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array($sample1);
$yummy   = array($sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);

// Provides: You should eat fruits, vegetables, and fiber every day.

如果我使用也一样：

$sample1 = '"fruits", "vegetables", "fiber"';
$sample1 = '"pizza", "beer", "ice cream"';
$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array($sample1);
$yummy   = array($sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);

我是不是漏掉了什么？

有没有办法轻松做到这一点？

Answer 1

您需要将字符串转为数组，在这种情况下使用爆炸：

$sample1 = "fruits, vegetables, fiber";
$sample2 = "pizza, beer, ice cream";
$phrase  = "You should eat fruits, vegetables, and fiber every day.";
    $healthy = explode(',',$sample1);
    $yummy   = explode(',',$sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);

Answer 2

您可以使用分隔符将 string分解为array：

$sample1 = "fruits, vegetables, fiber";
$sample2 = "pizza, beer, ice cream";
$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$healthy = explode(",", $sample1);
$yummy   = explode(",", $sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);

我建议您不要在每个字符串之间使用白色 space。如果您打算这样做，那么您可能需要 trim() 每个值。 array_map() 在这里很有用，因为您可以像这样将函数映射到每个值：

$healthy = array_map('trim', explode(",", $sample1));

所以整个事情会更像：

$sample1 = "fruits    ,    vegetables,fiber";
$sample2 = "pizza,      beer,ice cream";
$phrase  = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array_map('trim', explode(",", $sample1));
$yummy   = array_map('trim', explode(",", $sample2));
$newphrase = str_replace($healthy, $yummy, $phrase);

字符串替换为数组中的变量

String Replace With Variable In Array

php

arrays

str-replace