基于两列值的差异 - Google 电子表格

Question

我有以下挑战。

你能做的最好的事情就是看照片，这样你就能更好地理解它。我想在 Google 电子表格中动态显示预订约会之间的区别。

存在以下约会： = 新销售和赢回。

New Sales = 是新的约会，如果之前有none，那么就没有“lead_id”或者已经有“lead_id”，约会必须超过过去 30 天。
赢回 = 如果相同的“lead_id”在30天内再次被预订。

所以我想如果“lead_id”存在，那么最后一个日期从“lead_id”->“oppt_booked_on”减去当前日期“oppt_booked_on” ".

我试了很多，vlookp，match function等等，就是写不出动态公式。始终使用最后一次预订也很重要，如示例（照片）所示。我希望有一个人可以帮助我。非常感谢。

Answer 1

不确定这是否完全符合您的要求，但公式如下：

=datedif(index(sort(filter(F:F,A:A=A2)),match(F2,sort(filter(F:F,A:A=A2)),0)-1),F2,"d")

在 'Days between_booked on' 列（您的 J 列）中 return 行日期与同一 lead_id 前一个实例的日期之间的天数（列A).

此后，公式如下：

=if(and(countif(A:A,A2)>1,isbetween(J2,1,30)),"Winback","New Sales")

在 'Outcome'（您的第 I 列）中 return 如果当前行的 lead_id 实例超过 1 个，并且当前行和上一个相同的实例 lead_id 小于或等于 30 天。

Answer 2

不确定是否有意义，但这是脚本：

function main() {
  const ss = SpreadsheetApp.getActiveSpreadsheet();
  const sh = ss.getActiveSheet();
  const range = sh.getDataRange();
  const [header, ...rows] = range.getValues();

  // get indexes of the columns
  const col = {};
  col.id      = header.indexOf('lead_id')
  col.outcome = header.indexOf('Outcome');
  col.date    = header.indexOf('oppt_booked_on');
  col.days    = header.indexOf('Days Between booked_on');

  
  // create the object 'data' from the rows
    
  const data = {};
  for (let row in rows) {
    let id = rows[row][col.id];
  
    try {
      data[id].dates.push(rows[row][col.date]);
    }
    catch(e) {
      data[id] = {
        outcome: 'New Sales',
        days: '',
        dates: [rows[row][col.date]],
      }
    }
  }
  
  // change the rows
  
  for (let row in rows) {
    let id = rows[row][col.id];
    let obj = data[id];

    rows[row][col.outcome] = obj.outcome;
    rows[row][col.days] = obj.days;

    if (obj.dates.length > 1) {
      obj.days = days_between(obj.dates.shift(), obj.dates[0]);
      obj.outcome = (obj.days < 30) ? 'Winback' : 'New Sales';
    }
  }

  // set the columns 'Outcome' and 'Days...' on the sheet

  const outcome = rows.map(x => [x[col.outcome]]);
  sh.getRange(2, col.outcome+1, outcome.length, 1).setValues(outcome);

  const days = rows.map(x => [x[col.days]]);
  sh.getRange(2, col.days+1, days.length, 1).setValues(days);

}


// function returns number of days between two dates

function days_between(date1, date2) {
  let msec = Math.abs(date1.getTime() - date2.getTime());
  let days = Math.floor(msec/(1000*60*60*24));
  return days;
}

随时为您的电子表格修改它。

Answer 3

潜在客户分析

我想要可以复制和粘贴的数据来测试此代码：

function leadAnalysis() {
  const ss = SpreadsheetApp.getActive();
  const sh = ss.getSheetByName('Sheet0');
  const sr = 2;//data start row
  const vs = sh.getRange(sr, 1, sh.getLastRow() - sr + 1, 6).getValues();
  let lo = { lA: [] };
  vs.forEach((r, i) => {
    if (!lo.hasOwnProperty(r[0])) {
      lo[r[0]] = [];
      lo[r[0]].push({ lead_id: r[0], lead_name: r[1], booked_by: r[2], cars_on_search: r[3], sales_segment: r[4], oppt_booked_on: r[5], digital_consulant: r[6], 'Outcome': 'New Sales', days_between_booked_on: 0 });
      sh.getRange(i + sr, 9,1,2).setValues([[lo[r[0]][lo[r[0]].length-1].Outcome,lo[r[0]][lo[r[0]].length-1].days_between_booked_on]]);
      lo.lA.push(r[0]);
    } else {
      let d = DiffInDays1(new Date(lo[r[0]][lo[r[0]].length - 1].oppt_booked_on), new Date(r[5]))
      lo[r[0]].push({ lead_id: r[0], lead_name: r[1], booked_by: r[2], cars_on_search: r[3], sales_segment: r[4], oppt_booked_on: r[5], digital_consulant: r[6], 'Outcome': (d > 30) ? 'New Sales' : 'WinBack', days_between_booked_on: d });
      sh.getRange(i + sr, 9,1,2).setValues([[lo[r[0]][lo[r[0]].length-1].Outcome,lo[r[0]][lo[r[0]].length-1].days_between_booked_on]]);
    }
  })
}
function DiffInDays1(Day1, Day2) {
  if (Day1 && Day2 && (Object.prototype.toString.call(Day1) === '[object Date]') && (Object.prototype.toString.call(Day2) === '[object Date]')) {
    var day = 86400000;
    var t1 = new Date(Day1).valueOf();
    var t2 = new Date(Day2).valueOf();
    var d = Math.abs(t2 - t1);
    var days = Math.floor(d / day);
    //Logger.log(days);
    return days;
  } else {
    throw 'Invalid Inputs';
  }
}

通过自己输入得到如下数据如下：

lead_id	oppt_booked_on	Outcome	Days
id1	1/1/2021	New Sales	0
id2	1/2/2021	New Sales	0
id3	1/3/2021	New Sales	0
id4	1/4/2021	New Sales	0
id5	1/5/2021	New Sales	0
id6	1/6/2021	New Sales	0
id1	3/1/2021	New Sales	59
id2	3/2/2021	New Sales	59
id3	3/3/2021	New Sales	59
id4	3/4/2021	New Sales	59
id5	3/5/2021	New Sales	59
id6	3/6/2021	New Sales	59
id1	3/18/2021	WinBack	16
id2	3/19/2021	WinBack	16
id3	3/20/2021	WinBack	16
id4	3/21/2021	WinBack	16
id5	3/22/2021	WinBack	16
id6	3/23/2021	WinBack	16

这个版本会运行快得多：

function leadAnalysis() {
  const ss = SpreadsheetApp.getActive();
  const sh = ss.getSheetByName('Sheet0');
  const sr = 2;//data start row
  const vs = sh.getRange(sr, 1, sh.getLastRow() - sr + 1, 6).getValues();
  let lo = { lA: [] };
  let oA = [];
  vs.forEach((r, i) => {
    if (!lo.hasOwnProperty(r[0])) {
      lo[r[0]] = [];
      lo[r[0]].push({ lead_id: r[0], lead_name: r[1], booked_by: r[2], cars_on_search: r[3], sales_segment: r[4], oppt_booked_on: r[5], digital_consulant: r[6], 'Outcome': 'New Sales', days_between_booked_on: 0 });
      //sh.getRange(i + sr, 9,1,2).setValues([[lo[r[0]][lo[r[0]].length-1].Outcome,lo[r[0]][lo[r[0]].length-1].days_between_booked_on]]);
      oA.push([lo[r[0]][lo[r[0]].length-1].Outcome,lo[r[0]][lo[r[0]].length-1].days_between_booked_on])
      lo.lA.push(r[0]);
    } else {
      let d = DiffInDays1(new Date(lo[r[0]][lo[r[0]].length - 1].oppt_booked_on), new Date(r[5]))
      lo[r[0]].push({ lead_id: r[0], lead_name: r[1], booked_by: r[2], cars_on_search: r[3], sales_segment: r[4], oppt_booked_on: r[5], digital_consulant: r[6], 'Outcome': (d > 30) ? 'New Sales' : 'WinBack', days_between_booked_on: d });
      //sh.getRange(i + sr, 9,1,2).setValues([[lo[r[0]][lo[r[0]].length-1].Outcome,lo[r[0]][lo[r[0]].length-1].days_between_booked_on]]);
      oA.push([lo[r[0]][lo[r[0]].length-1].Outcome,lo[r[0]][lo[r[0]].length-1].days_between_booked_on]);
    }
  })
  sh.getRange(sr,9,oA.length,oA[0].length).setValues(oA)
}

基于两列值的差异 - Google 电子表格

Differentiation based on two columns values - Google Spreadsheet

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