根据重复计数区分和排序集合

Question

我有以下合集

$collection = collect([
    ['id' => 1, 'name' => 'Design'],
    ['id' => 2, 'name' => 'Art'],
    ['id' => 3, 'name' => 'Comms'],
    ['id' => 2, 'name' => 'Art'],
    ['id' => 3, 'name' => 'Comms'],
    ['id' => 3, 'name' => 'Comms'],
]);

我只想要集合中唯一的项目，集合应按重复项数排序。因此，重复次数最多的项目必须出现在顶部，如下所示

$collection = collect([
        ['id' => 3, 'name' => 'Comms'],
        ['id' => 2, 'name' => 'Art'],
        ['id' => 1, 'name' => 'Design'],
    ]);

我可以使用 unique 方法删除重复项，但找不到要对它们进行排序的方法。

Answer 1

你可以用 mapWithKeys()

https://laravel.com/docs/8.x/collections#method-mapwithkeys

$collection = $collection->groupBy('id')->mapWithKeys(function (Collection $row) {
    return [$row->count() => $row->first()];
})->sortKeysDesc();

根据重复计数区分和排序集合

Distinct and sort collection based on duplicate count

laravel

laravel-collection