在 Python 中将 JSON 文件扁平化为 Pandas 数据框

Question

我有 json 这种格式：

{
    "fields": {
        "tcidte": {
            "mode": "required",
            "type": "date",
            "format": "%Y%m%d"
        },
        "tcmcid": {
            "mode": "required",
            "type": "string"
        },
        "tcacbr": {
            "mode": "required",
            "type": "string"
        }
    }
}

我希望它采用数据帧格式，其中三个字段名称中的每一个都是单独的行。其中一行有一列（例如“格式”），而其他行为空的列应假定为 NULL。

我已尝试使用我在此处找到的 flatten_json 功能，但没有按预期工作，但仍会在此处包括：

def flatten_json(nested_json, exclude=['']):
    """Flatten json object with nested keys into a single level.
        Args:
            nested_json: A nested json object.
            exclude: Keys to exclude from output.
        Returns:
            The flattened json object if successful, None otherwise.
    """
    out = {}

    def flatten(x, name='', exclude=exclude):
        if type(x) is dict:
            for a in x:
                if a not in exclude: flatten(x[a], name + a + '_')
        elif type(x) is list:
            i = 0
            for a in x:
                flatten(a, name + str(i) + '_')
                i += 1
        else:
            out[name[:-1]] = x

    flatten(nested_json)
    return out

flatten_json_file = pd.DataFrame(flatten_json(nested_json))
pprint.pprint(flatten_json_file)

额外的复杂性JSON：

{
    "fields": {
        "action": {
            "type": {
                "field_type": "string"
            },
            "mode": "required"
        },
        "upi": {
            "type": {
                "field_type": "string"
            },
            "regex": "^[0-9]{9}$",
            "mode": "required"
        },
        "firstname": {
            "type": {
                "field_type": "string"
            },
            "mode": "required"
        }
    }
}

Answer 1

一个选项是 jmespath 库，它在以下场景中很有用：

# pip install jmespath
import jmespath
import pandas as pd

# think of it like a path 
# fields is the first key
# there are sub keys with varying names
# we are only interested in mode, type, format
# hence the * to represent the intermediate key(s)
expression = jmespath.compile('fields.*[mode, type, format]')

pd.DataFrame(expression.search(data), columns = ['mode', 'type', 'format'])

       mode    type  format
0  required    date  %Y%m%d
1  required  string    None
2  required  string    None

jmespath 有很多工具；然而，这应该足够了，并且涵盖了子词典中缺少键（模式、类型、格式）的场景。

Answer 2

df= pd.read_json('test.json')
df_fields = pd.DataFrame(df['fields'].values.tolist(), index=df.index)
print(df_fields)

输出：

            mode    type  format
tcacbr  required  string     NaN
tcidte  required    date  %Y%m%d
tcmcid  required  string     NaN

Answer 3

有

data = {
    "fields": {
        "tcidte": {
            "mode": "required",
            "type": "date",
            "format": "%Y%m%d"
        },
        "tcmcid": {
            "mode": "required",
            "type": "string"
        },
        "tcacbr": {
            "mode": "required",
            "type": "string"
        }
    }
}

这个

df = pd.DataFrame(data["fields"].values())

结果

       mode    type  format
0  required    date  %Y%m%d
1  required  string     NaN
2  required  string     NaN

这是你的目标吗？

如果你想要data["fields"]的键作为索引：

df = pd.DataFrame(data["fields"]).T

或

df = pd.DataFrame.from_dict(data["fields"], orient="index")

两者都导致

            mode    type  format
tcidte  required    date  %Y%m%d
tcmcid  required  string     NaN
tcacbr  required  string     NaN

有

data = {
    "fields": {
        "action": {
            "type": {
                "field_type": "string"
            },
            "mode": "required"
        },
        "upi": {
            "type": {
                "field_type": "string"
            },
            "regex": "^[0-9]{9}$",
            "mode": "required"
        },
        "firstname": {
            "type": {
                "field_type": "string"
            },
            "mode": "required"
        }
    }
}

你可以做

data = {key: {**d, **d["type"]} for key, d in data["fields"].items()}
df = pd.DataFrame.from_dict(data, orient="index").drop(columns="type")

或

df = pd.DataFrame.from_dict(data["fields"], orient="index")
df = pd.concat(
    [df, pd.DataFrame(df.type.to_list(), index=df.index)], axis=1
).drop(columns="type")

结果类似（列位置可能不同）

               mode field_type       regex
action     required     string         NaN
upi        required     string  ^[0-9]{9}$
firstname  required     string         NaN

在 Python 中将 JSON 文件扁平化为 Pandas 数据框

Flatting a JSON file into Pandas Dataframe in Python

python

json

dataframe

pandas

json-flattener