大于或小于在 if 语句中不起作用的值

Question

我在处理一段测试代码时遇到了一些问题。我还是新手，如果让您感到困惑，我深表歉意。我试着做一个小骰子游戏，如果你得到更高的价值，你就会赢。但每次它只会说我赢了，我不知道为什么。如果很明显，我很抱歉，我似乎无法弄清楚。

mylist = {"Yes", "Sure", "yes", "sure"}
mylist2 = {"No", "Nope", "no", "nope"}

print("Dice game test")

def opponent():
    opponent = random.randint(1,6)
    return(f'He rolled a {opponent}')
o = opponent()

def player():
    player = random.randint(1,6)
    return(f'You rolled a {player}')
p = player()

answer = input("Ready to roll?")
if answer in mylist:
    if (p > o):
        print(f'{p} and {o}. You won, Test complete')
    elif (o > p):
        print(f'{p} and {o}. You lost, Test complete')
    elif (p == o):
        print(f'{p} and {o}. You got a tie, Test Complete')
    else:
        print("An error occurred")
else:
    print("Wrong input")

基本上它似乎只告诉我我赢了，即使文本中显示的玩家数字小于对手也是如此。我只是想弄清楚如何让它正确显示数字并与输赢文本相匹配。

Answer 1

你的问题是你 return 一个字符串而不是随机整数。

您的代码应如下所示：

mylist = {"Yes", "Sure", "yes", "sure"}
mylist2 = {"No", "Nope", "no", "nope"}

print("Dice game test")

def getopponent():
    opp = 4
    print(f'He rolled a {opp}')
    return opp
o = getopponent()

def getplayer():
    player = 1
    print(f'You rolled a {player}')
    return player
p = getplayer()

answer = input("Ready to roll?")
if answer in mylist:
    if (p > o):
        print(f'{p} and {o}. You won, Test complete')
    elif (o > p):
        print(f'{p} and {o}. You lost, Test complete')
    elif (p == o):
       print(f'{p} and {o}. You got a tie, Test Complete')
    else:
        print("An error occurred")
else:
    print("Wrong input")

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