ERROR: 'NoneType' object has no attribute 'find_all'
ERROR: 'NoneType' object has no attribute 'find_all'
我正在对一个名为:CVE Trends
的网页进行网络抓取
import bs4, requests,webbrowser
LINK = "https://cvetrends.com/"
PRE_LINK = "https://nvd.nist.gov/"
response = requests.get(LINK)
response.raise_for_status()
soup=bs4.BeautifulSoup(response.text,'html.parser')
div_tweets=soup.find('div',class_='tweet_text')
a_tweets=div_tweets.find_all('a')
link_tweets =[]
for a_tweet in a_tweets:
link_tweet= str(a_tweet.get('href'))
if PRE_LINK in link_tweet:
link_tweets.append(link_tweet)
from pprint import pprint
pprint(link_tweets)
这是我到目前为止编写的代码。我尝试了很多方法,但它总是给出相同的错误:
'NoneType'对象没有属性'find_all'
有人可以帮帮我吗?我真的需要这个。
提前感谢您的回答。
发生这种情况是因为 soup.find("div", class_="tweet_text")
没有找到任何东西,所以它 returns None
。发生这种情况是因为您尝试抓取的网站是使用 javascript 填充的,因此当您向该网站发送获取请求时,这就是您要返回的内容:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8"/>
<meta content="width=device-width, initial-scale=1, shrink-to-fit=no" name="viewport"/>
<title>
CVE Trends - crowdsourced CVE intel
</title>
<meta content="Monitor real-time, crowdsourced intel about trending CVEs on Twitter." name="description"/>
<meta content="trending CVEs, CVE intel, CVE trends" name="keywords"/>
<meta content="CVE Trends - crowdsourced CVE intel" name="title" property="og:title">
<meta content="Simon Bell" name="author"/>
<meta content="website" property="og:type">
<meta content="https://cvetrends.com/images/cve-trends.png" name="image" property="og:image">
<meta content="https://cvetrends.com" property="og:url">
<meta content="Monitor real-time, crowdsourced intel about trending CVEs on Twitter." property="og:description"/>
<meta content="en_GB" property="og:locale"/>
<meta content="en_US" property="og:locale:alternative"/>
<meta content="CVE Trends" property="og:site_name"/>
<meta content="summary_large_image" name="twitter:card"/>
<meta content="@SimonByte" name="twitter:creator"/>
<meta content="CVE Trends - crowdsourced CVE intel" name="twitter:title"/>
<meta content="Monitor real-time, crowdsourced intel about trending CVEs on Twitter." name="twitter:description"/>
<meta content="https://cvetrends.com/images/cve-trends.png" name="twitter:image"/>
<link href="https://cvetrends.com/favicon.ico" id="favicon" rel="icon" sizes="32x32"/>
<link href="https://cvetrends.com/apple-touch-icon.png" id="apple-touch-icon" rel="apple-touch-icon"/>
<link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/5.1.0/css/bootstrap.min.css" rel="stylesheet"/>
</meta>
</meta>
</meta>
</meta>
</head>
<body>
<div id="root">
</div>
<noscript>
Please enable JavaScript to run this app.
</noscript>
<script src="https://cvetrends.com/js/main.d0aa7136854f54748577.bundle.js">
</script>
</body>
</html>
您可以使用 print(soup.prettify())
来验证这一点。
要抓取此站点,您可能必须使用类似 Selenium 的工具。
这是因为没有得到您真正想要的响应。
本网站有java脚本加载的内容,因此您不会在请求中获取数据。
您将从 https://cvetrends.com/api/cves/24hrs
获取数据,而不是抓取网站
这里有一些解决方案:
import requests
import json
from urlextract import URLExtract
LINK = "https://cvetrends.com/api/cves/24hrs"
PRE_LINK = "https://nvd.nist.gov/"
link_tweets = []
# library for url extraction
extractor = URLExtract()
# ectract response from LINK (json Response)
html = requests.get(LINK).text
# convert string to json object
twitt_json = json.loads(html)
twitt_datas = twitt_json.get('data')
for twitt_data in twitt_datas:
# extract tweets
twitts = twitt_data.get('tweets')
for twitt in twitts:
# extract tweet texts and validate condition
twitt_text = twitt.get('tweet_text')
if PRE_LINK in twitt_text:
# find urls from text
urls_list = extractor.find_urls(twitt_text)
for url in urls_list:
if PRE_LINK in url:
link_tweets.append(twitt_text)
print(link_tweets)
我正在对一个名为:CVE Trends
的网页进行网络抓取import bs4, requests,webbrowser
LINK = "https://cvetrends.com/"
PRE_LINK = "https://nvd.nist.gov/"
response = requests.get(LINK)
response.raise_for_status()
soup=bs4.BeautifulSoup(response.text,'html.parser')
div_tweets=soup.find('div',class_='tweet_text')
a_tweets=div_tweets.find_all('a')
link_tweets =[]
for a_tweet in a_tweets:
link_tweet= str(a_tweet.get('href'))
if PRE_LINK in link_tweet:
link_tweets.append(link_tweet)
from pprint import pprint
pprint(link_tweets)
这是我到目前为止编写的代码。我尝试了很多方法,但它总是给出相同的错误:
'NoneType'对象没有属性'find_all'
有人可以帮帮我吗?我真的需要这个。 提前感谢您的回答。
发生这种情况是因为 soup.find("div", class_="tweet_text")
没有找到任何东西,所以它 returns None
。发生这种情况是因为您尝试抓取的网站是使用 javascript 填充的,因此当您向该网站发送获取请求时,这就是您要返回的内容:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8"/>
<meta content="width=device-width, initial-scale=1, shrink-to-fit=no" name="viewport"/>
<title>
CVE Trends - crowdsourced CVE intel
</title>
<meta content="Monitor real-time, crowdsourced intel about trending CVEs on Twitter." name="description"/>
<meta content="trending CVEs, CVE intel, CVE trends" name="keywords"/>
<meta content="CVE Trends - crowdsourced CVE intel" name="title" property="og:title">
<meta content="Simon Bell" name="author"/>
<meta content="website" property="og:type">
<meta content="https://cvetrends.com/images/cve-trends.png" name="image" property="og:image">
<meta content="https://cvetrends.com" property="og:url">
<meta content="Monitor real-time, crowdsourced intel about trending CVEs on Twitter." property="og:description"/>
<meta content="en_GB" property="og:locale"/>
<meta content="en_US" property="og:locale:alternative"/>
<meta content="CVE Trends" property="og:site_name"/>
<meta content="summary_large_image" name="twitter:card"/>
<meta content="@SimonByte" name="twitter:creator"/>
<meta content="CVE Trends - crowdsourced CVE intel" name="twitter:title"/>
<meta content="Monitor real-time, crowdsourced intel about trending CVEs on Twitter." name="twitter:description"/>
<meta content="https://cvetrends.com/images/cve-trends.png" name="twitter:image"/>
<link href="https://cvetrends.com/favicon.ico" id="favicon" rel="icon" sizes="32x32"/>
<link href="https://cvetrends.com/apple-touch-icon.png" id="apple-touch-icon" rel="apple-touch-icon"/>
<link href="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/5.1.0/css/bootstrap.min.css" rel="stylesheet"/>
</meta>
</meta>
</meta>
</meta>
</head>
<body>
<div id="root">
</div>
<noscript>
Please enable JavaScript to run this app.
</noscript>
<script src="https://cvetrends.com/js/main.d0aa7136854f54748577.bundle.js">
</script>
</body>
</html>
您可以使用 print(soup.prettify())
来验证这一点。
要抓取此站点,您可能必须使用类似 Selenium 的工具。
这是因为没有得到您真正想要的响应。
本网站有java脚本加载的内容,因此您不会在请求中获取数据。
您将从 https://cvetrends.com/api/cves/24hrs
获取数据,而不是抓取网站这里有一些解决方案:
import requests
import json
from urlextract import URLExtract
LINK = "https://cvetrends.com/api/cves/24hrs"
PRE_LINK = "https://nvd.nist.gov/"
link_tweets = []
# library for url extraction
extractor = URLExtract()
# ectract response from LINK (json Response)
html = requests.get(LINK).text
# convert string to json object
twitt_json = json.loads(html)
twitt_datas = twitt_json.get('data')
for twitt_data in twitt_datas:
# extract tweets
twitts = twitt_data.get('tweets')
for twitt in twitts:
# extract tweet texts and validate condition
twitt_text = twitt.get('tweet_text')
if PRE_LINK in twitt_text:
# find urls from text
urls_list = extractor.find_urls(twitt_text)
for url in urls_list:
if PRE_LINK in url:
link_tweets.append(twitt_text)
print(link_tweets)