使用 seaborn 的单个箱线图中的多列

Question

与此相关

我想像这样将它们分组到一个箱线图中。

但是我在使用这段代码时遇到了问题。

cn = ['AgeUnder18', 'Age19to25', 'Age26to29']
sns.boxplot(x=cn, y='AveMonthSpend', data=df)

错误：

The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

Answer 1

您需要将数据帧转换为 "long form":

import matplotlib.pyplot as plt
import seaborn as sns
import pandas as pd
import numpy as np

cn = ['AgeUnder18', 'Age19to25', 'Age26to29']
df = pd.DataFrame({age_group: np.random.uniform(45, 65, 7) for age_group in cn})
df_melted = df.melt(value_vars=cn, value_name='AveMonthSpend', var_name='Age Bin')
sns.boxplot(y='Age Bin', x='AveMonthSpend', data=df_melted, palette='Greys')
plt.tight_layout()
plt.show()

假设原始数据框如下所示：

Out[10]: 
   AgeUnder18  Age19to25  Age26to29
0   64.980248  64.673755  56.489776
1   59.858895  48.921889  62.877826
2   62.357871  51.599347  55.651448
3   47.206124  45.817266  52.893839
4   57.627501  51.820863  59.616511
5   61.999523  63.443241  45.919390
6   56.616062  48.353018  46.282314

使用 seaborn 的单个箱线图中的多列

Multiple column in a single boxplot using seaborn

python

boxplot

pandas

seaborn

jupyter-notebook