比较 2 个对象的值并将值推送到一个对象数组

Comparing 2 objects' values and push the values to one object array

我正在尝试通过 属性 和值来比较 2 个对象。如果“名称”属性 的值彼此匹配,我想将 属性 和值推送到 value3.

记录 value3 后,我想要这样的响应:

{
name: 'dog',
surname: 'good',
skills: 'programming',
age: '22'
},
{
name: 'cat',
surname: 'soft',
skills: 'engineer'
age: '12'
},
{
name: 'elephant',
surname: 'big',
skills: 'programming'
age: '23'
}

代码如下:

var values1 = [
    {
    name: 'dog',
    surname: 'good',
    skills: 'programming'
    },
    {
    name: 'cat',
    surname: 'soft',
    skills: 'engineer'
    },
    {
    name: 'elephant',
    surname: 'big',
    skills: 'programming'
    }
]

var values2 = [
    {
    name: 'cat',
    food: 'fish',
    age: '12'
    },
    {
    name: 'elephant',
    food: 'leafs',
    age: '13'
    },
    {
    name: 'dog',
    food: 'treats',
    age: '22'
    }
]

// push into this empty object array
var values3 = [{}]

console.log(values3)

const values1 = [
  { name: 'dog', surname: 'good', skills: 'programming' },
  { name: 'cat', surname: 'soft', skills: 'engineer' },
  { name: 'elephant', surname: 'big', skills: 'programming' }
]

const values2 = [
  { name: 'cat', food: 'fish', age: '12' },
  { name: 'elephant', food: 'leafs', age: '13' },
  { name: 'dog', food: 'treats', age: '22' }
]

const values3 = values1.map((value1) => {
  return Object.assign(value1, { age: values2.filter(value2 => value2.name === value1.name)[0].age })
})

console.log(values3)

上面的代码只有在 values1 中的每个 name 对象具有 name[=24= 时才有效] 存在于 values2 中。如果不使用此代码:

const values3 = values1.map((value1) => {
  const found = values2.find(value2 => value2.name === value1.name)
  return Object.assign(value1, { age: found ? found.age : undefined })
})