可以 Python Subprocess.Popen handle/ignore Electron 应用程序启动时出现 ENOENT 错误并像在命令行中一样继续前进

Question

subprocess.open 抛出错误生成。/jre/bin/java ENOENT 异常

import subprocess
subprocess.run([r"C:\Users\<user>\AppData\Local\Programs\<some_dir>\<some_tool>.exe", "--args", "--remote-debugging-port=9000"])

也试过了，

subprocess.Popen([r"C:\Users\<user>\AppData\Local\Programs\<some_dir>\<some_tool>.exe", "--args", "--remote-debugging-port=9000"])

也尝试了Popen中的shell=True参数但没有解决

手动启动此应用程序不会导致任何问题。

不确定是什么导致了这个问题 - 我该如何解决？
当我运行 this from command 有类似的出现在控制台输出但没有出现阻塞对话框并且应用程序出现没有崩溃 - 我有什么办法可以

同样复制 python 的非崩溃行为。

命令行输出如下：

c:\Users\<user>\AppData\Local\Programs\<base_dir>>
18:56:05.542 > Start in production mode
18:56:05.585 > electron-log.transports.file: Can't write to c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\logs\main.log Error: ENOTDIR, not a directory
    at createError (electron/js2c/asar_bundle.js:5:1382)
    at Object.e.mkdirSync (electron/js2c/asar_bundle.js:5:12161)
    at e (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:249748)
    at l.testFileWriting (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:249938)
    at l.createFile (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:249488)
    at l.provide (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:249315)
    at d (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:246666)
    at h (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:246165)
    at i (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:47829)
    at n (c:\Users\<user>\AppData\Local\Programs\<base_dir>\resources\app.asar\background.js:1:47621)
18:56:05.606 > Launching server at backend\<application>-backend-0.0.1-SNAPSHOT.jar at port 8885...
18:56:05.724 > Server PID: 69044
18:56:10.731 >
18:56:10.733 >   .   ____          _            __ _ _
18:56:10.737 >  /\ / ___'_ __ _ _(_)_ __  __ _ \ \ \ \
18:56:10.739 > ( ( )\___ | '_ | '_| | '_ \/ _` | \ \ \ \
18:56:10.740 >  \/  ___)| |_)| | | | | || (_| |  ) ) ) )
18:56:10.741 >   '  |____| .__|_| |_|_| |_\__, | / / / /
18:56:10.742 >  =========|_|==============|___/=/_/_/_/
18:56:10.744 >  :: Spring Boot ::                (v2.5.4)
18:56:10.745 >
18:56:11.126 > 2021-12-10 18:56:11.119  INFO 69044 --- [           main] p.core.<application>BackendApplication  : Starting <application>BackendApplication using Java 11.0.13 on G1-6FWX7C3-L with PID 69044 (C:\Users\<user>\AppData\Local\Programs\<base_dir>\backend\<application>-backend-0.0.1-SNAPSHOT.jar started by <user> in c:\Users\<user>\AppData\Local\Programs\<base_dir>)
18:56:11.127 > 2021-12-10 18:56:11.126  INFO 69044 --- [           main] p.core.<application>BackendApplication  : No active profile set, falling back to default profiles: default
18:56:18.360 > 2021-12-10 18:56:18.359  INFO 69044 --- [           main] o.s.b.w.embedded.tomcat.TomcatWebServer  : Tomcat initialized with port(s): 8885 (http)
18:56:18.446 > 2021-12-10 18:56:18.444  INFO 69044 --- [           main] o.apache.catalina.core.StandardService   : Starting service [Tomcat]
18:56:18.447 > 2021-12-10 18:56:18.445  INFO 69044 --- [           main] org.apache.catalina.core.StandardEngine  : Starting Servlet engine: [Apache Tomcat/9.0.52]
18:56:18.889 > 2021-12-10 18:56:18.887  INFO 69044 --- [           main] o.a.c.c.C.[Tomcat].[localhost].[/]       : Initializing Spring embedded WebApplicationContext
18:56:18.891 > 2021-12-10 18:56:18.888  INFO 69044 --- [           main] w.s.c.ServletWebServerApplicationContext : Root WebApplicationContext: initialization completed in 7499 ms
18:56:23.934 > 2021-12-10 18:56:23.933  INFO 69044 --- [           main] o.s.b.a.e.web.EndpointLinksResolver      : Exposing 14 endpoint(s) beneath base path '/rest/actuator'
18:56:24.174 > 2021-12-10 18:56:24.172  INFO 69044 --- [           main] o.s.b.w.embedded.tomcat.TomcatWebServer  : Tomcat started on port(s): 8885 (http) with context path ''
18:56:24.241 > 2021-12-10 18:56:24.241  INFO 69044 --- [           main] p.core.<application>BackendApplication  : Started <application>BackendApplication in 15.385 seconds (JVM running for 17.665)
18:56:24.644 > 2021-12-10 18:56:24.642  INFO 69044 --- [nio-8885-exec-1] o.a.c.c.C.[Tomcat].[localhost].[/]       : Initializing Spring DispatcherServlet 'dispatcherServlet'
18:56:24.645 > 2021-12-10 18:56:24.643  INFO 69044 --- [nio-8885-exec-1] o.s.web.servlet.DispatcherServlet        : Initializing Servlet 'dispatcherServlet'
18:56:24.657 > 2021-12-10 18:56:24.647  INFO 69044 --- [nio-8885-exec-1] o.s.web.servlet.DispatcherServlet        : Completed initialization in 4 ms

Answer 1

好的 - 所以 Electron Package 与它自己的 jre 版本捆绑在一起，这导致了问题，因为调用 exe 导致 JAVA 依赖项在系统默认情况下被查找jre 路径而不是与 Electron 应用程序捆绑在一起的路径。

解决方案 - 切换到应用程序的基本目录，然后启动它：

import subprocess, os
from subprocess import *
os.chdir(r"C:\app_dir")
subprocess.Popen(['app.exe'])

希望这对面临类似问题的人有所帮助。

可以 Python Subprocess.Popen handle/ignore Electron 应用程序启动时出现 ENOENT 错误并像在命令行中一样继续前进

Could Python Subprocess.Popen handle/ignore ENOENT error on Electron app launch and proceed ahead without fail as in command line

python

java

electron

subprocess

enoent