在数据框上使用 rapidfuzz

Question

我有 4 列，分别是 BuisnessID、姓名、BuisnessID_y、Name_y，我想将姓名与 Name_y 匹配，相似度得分为 90%，如果不是 90%然后删除那些行。样本输入

df

BusinessID      NAME        BusinessID_y  NAME_y

1013120869  MANOJ WANKHADE  1013404164    SLIMI
1013120869  MANOJ WANKHADE  1013831688    AMOL SHAHAKAR
1013120869  MANOJ WANKHADE  1013376009    PRATHMESH AGRAWAL
1013120869  MANOJ WANKHADE  1013376009    PRATHMESH AGRAWAL
1013120869  MANOJ WANKHADE  1013478922    AMBRISH PANDRIKAR

我是 python 的新手，不知道该怎么做。此外，我有 500k 条记录，因此任何其他快速模糊测试方法都很棒

Answer 1

>>> import pandas as pd
>>> import rapidfuzz
>>> df['matching_ratio'] = df.apply(lambda x:rapidfuzz.fuzz.ratio(x.NAME, x.NAME_y), axis=1).to_list()
>>> df

   BusinessID            NAME  BusinessID_y             NAME_y  matching_ratio
0  1013120869  MANOJ WANKHADE    1013404164              SLIMI       10.526316
1  1013120869  MANOJ WANKHADE    1013831688      AMOL SHAHAKAR       44.444444
2  1013120869  MANOJ WANKHADE    1013376009  PRATHMESH AGRAWAL       25.806452
3  1013120869  MANOJ WANKHADE    1013376009  PRATHMESH AGRAWAL       25.806452
4  1013120869  MANOJ WANKHADE    1013478922  AMBRISH PANDRIKAR       38.709677


>>> df[df.matching_ratio > 26] # change this '26' value to '90' as your requirmetn

   BusinessID            NAME  BusinessID_y             NAME_y  matching_ratio
1  1013120869  MANOJ WANKHADE    1013831688      AMOL SHAHAKAR       44.444444
4  1013120869  MANOJ WANKHADE    1013478922  AMBRISH PANDRIKAR       38.709677

在数据框上使用 rapidfuzz

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