Django 中的 DetailView，关键字 'slug'

Question

我最近开始学习 Django。我想显示一条新闻，但是当我打开 link 时，我收到一条错误消息：

Cannot resolve keyword 'slug' into field. Choices are: NewsTitles, NewsContent, NewsSlug
Request Method: GET
Request URL:    http://127.0.0.1:8000/news/nam-gravida-purus-non/
Django Version: 4.0
Exception Type: FieldError

views.py

from django.views.generic import DetailView
from .models import News

class GetNews(DetailView):
    model = News
    slug_url_kwarg = 'NewsSlug'
    template_name = 'news/single_news.html'
    context_object_name = 'single_news'
    allow_empty = False

urls.py

from django.urls import path
from .views import GetNews

urlpatterns = [
    path('news/<str:NewsSlug>/', GetNews.as_view(), name='news'),
]

models.py

from django.db import models
from django.urls import reverse_lazy

class News(models.Model):
    NewsTitles = models.CharField(max_length=120)
    NewsContent = models.TextField(max_length=255)
    NewsSlug = models.SlugField(max_length=255)

    def __str__(self):
        return self.NewsTitles

    def get_absolute_url(self):
        return reverse_lazy('news', kwargs={'NewsSlug': self.NewsSlug})

我做错了什么？

Answer 1

首先，不要用大写而是小写“newslug”或更好的“new_slug”来称呼您的 slug“NewSlug”，名称本身也应该更具描述性。

最后您需要告诉您的视图要使用哪个字段，您可以使用以下属性来定义它：

slug_field = "NewSlug"

注意 : class 的属性不应该是驼峰而是蛇形

Django 中的 DetailView，关键字 'slug'

DetailView in Django, keyword 'slug'

python

django

django-models

django-urls

django-views