NEO4J 查找与集合中的所有节点有关系 (direct/indirect) 的任何节点

Question

我是 neo4j 的新手，所以我可能在这里犯了一些基本错误：

这是我的图表的一个子集：

我有3种节点：

（蓝色）属性
（红色）业务
（黄色）促销

attributes 可以与 promotions 和 businesses (:TAGS)

有关系

这是我迄今为止最好的猜测密码查询。

MATCH(a:Attribute)--(b:Business)--(p:Promotion)
WHERE a.name IN ["business", "casual", "happy_hour"]
RETURN a, b, p
UNION
MATCH(a:Attribute)--(p:Promotion)--(b:Business)
WHERE a.name IN ["business", "casual", "happy_hour"]
RETURN a, b, p;

这不是我想要的，它 returns promotions 与 一个或多个 attributes

我只想 return promotions 与给定属性集中的 all attributes 有关系。我应该怎么做？

Answer 1

这应该有效。

// create collection of myTagNodes
WITH ["business", "casual", "happy_hour"] AS myTags
MATCH (myTagNode:TAG) WHERE myTagNode.name IN myTags
WITH COLLECT(myTagNode) AS myTagNodes

// only return promotions for which all 'myTagNodes'are in the 
// (indirectly) connected tags, i.e. through buisnesses or directly
MATCH (p:Promotion)
     WHERE ALL(myTagNode IN myTagNodes 
               WHERE myTagNode IN [(p)<-[*1..2]-(pTagNode:TAG) | pTagNode] 
           )
RETURN p

另见 https://neo4j.com/docs/developer-manual/current/cypher/syntax/lists/#cypher-list-comprehension 和 https://neo4j.com/docs/developer-manual/current/cypher/syntax/lists/#cypher-pattern-comprehension

NEO4J 查找与集合中的所有节点有关系 (direct/indirect) 的任何节点

NEO4J find any nodes that have relationships (direct/indirect) with all nodes in a set

neo4j

cypher

neo4j-ogm