比较 Python 中的多个列表

Question

我有 7 个 IP 地址列表：

    list_1 = ['192.168.0.1', '77.1.15.2', '30.24.15.7', '8.8.8.8', '5.6.13.8']
    list_2 = ['12.38.75.64', '30.24.15.7', '192.168.0.1']
    list_3 = ['6.15.79.64', '15.127.17.4', '192.168.0.1', '0.0.0.0', '74.58.69.14']
    list_4 = ['45.54.45.54', '89.98.89.98', '192.168.3.7', '192.168.4.12']
    list_5 = ['192.168.8.1', '192.168.0.1', '30.24.15.7', '192.168.7.24']
    list_6 = ['192.168.8.2', '192.168.8.3', '192.168.8.4', '15.127.17.4', '192.168.0.1']
    list_7 = ['192.168.0.1', '8.8.8.8']

如何比较所有列表并获得出现不止一次的IP，以及这些IP出现的次数？ IP数 192.168.0.1 = 6 30.24.15.7 = 3 8.8.8.8 = 2 15.127.17.4 = 2

Answer 1

使用 itertools 和 pandas 你可以：

import itertools
import pandas as pd

# chain all lists
l = list(itertools.chain(list_1, list_2, list_3, list_4, list_5, list_6, list_7))

# convert them to a Pandas Series and count values
counts = pd.Series(l).value_counts()

# only multiple occurrences
greaterThan1 = counts[counts>1]

并显示 greaterThan1 您将得到：

192.168.0.1    6
30.24.15.7     3
15.127.17.4    2
8.8.8.8        2

Answer 2

使用 Counter class 来计算 IP:

from collections import Counter
ctr = Counter()
ctr.update(list_1)
ctr.update(list_2)
# [...] repeat for all lists

# [...] Use the counts as needed
print(ctr)

如果您想要 key/value 对出现不止一次的项目：

more_than_once = {k:v for k,v in ctr.items() if v>1}
print(more_than_once)

比较 Python 中的多个列表

Compare many lists in Python

python

compare