格式化带有特殊字符的字符串

Format string with special character

我有一些带有特殊字符的字符串,我想删除这些字符。

def clean_special(input: str):  # This function is my cleaner
    # Idk how change these '.replace()' to something more efficient
    cleaning = re.sub(r'[()&.-]', ' ', input).replace("’", '')
    cleaning = cleaning.replace(',', '').replace("'", '').replace("[", '').replace("]", '').strip()
    return " ".join(cleaning.split())


original_string = 'Sabai, With Løve & Nevve - Falling For You (Official Music Video)'  # Title of music, with some special characters
cleaned_string = clean_special(original_string)
print(f'{original_string=}\n{cleaned_string=}')

它可以工作,但是当我有像 「Future Core」... 这样的特殊字符时就会中断

所以我尝试了其他方式:

string = '「Future Core」[lapix] Carry Me Away (Extended Mix)'

print(''.join(i for i in string if i.isalnum()))

并且有效,但现在有一个连接的字符串,我想要类似 Future Core lapix Carry Me Away Extended Mix 的东西,像第一次尝试一样有空格。

有人可以帮助我吗? ;-

I need these returns from code: Sabai With Løve Nevve Falling For You Official Music Video and Future Core lapix Carry Me Away Extended Mix

已解决的代码

string = '「Future Core」[lapix] Carry Me Away (Extended Mix)'

print(''.join(i for i in string if i.isalnum() or i.isspace()))

def clean_special(input: str):
    cleaning = re.sub(r'[^\w\s]+', '', input)
    return " ".join(cleaning.split())


string = '「Future Core」[lapix] Carry Me Away (Extended Mix)'
print(clean_special(string))