形状优美的 LineString 的飞行路径不正确
Flight Path by shapely LineString is not correct
我想将始发地 (lat_1 lon_1) 的飞机连接到目的地 (lat_2 lon_2)。我使用 these 数据。
callsign
latitude_1
longitude_1
latitude_2
longitude_2
0
HBAL102
-4.82114
-76.3194
-4.5249
-79.0103
1
AUA1028
-33.9635
151.181
48.1174
16.55
2
ABW120
41.9659
-87.8832
55.9835
37.4958
3
CSN461
33.9363
-118.414
50.0357
8.5723
4
ETH3730
25.3864
55.4221
50.6342
5.43903
但不幸的是,在使用 shapely 创建 LineString 时,我会得到不正确的结果。我使用了旋转和仿射等所有方法,但它没有正确。
代码:
cols = pd.read_csv("/content/dirct_lines.csv",sep=";")
line = cols[["callsign","latitude_1","longitude_1","latitude_2","longitude_2"]].dropna()
line['geometry'] = line.apply(lambda x: [(x['latitude_1'],
x['longitude_1']),
(x['latitude_2'],
x['longitude_2'])], axis = 1)
geoline = gpd.GeoDataFrame(line,geometry="geometry",
crs="EPSG:4326")
import matplotlib.pyplot as plt
world = gpd.read_file(gpd.datasets.get_path('naturalearth_lowres'))
ax = world.plot(figsize=(14,9),
color='white', edgecolor='black')
geoline.plot(figsize=(14,9),ax=ax,facecolor = 'lightgrey', linewidth = 1.75,
edgecolor = 'red',
alpha = 2)
plt.show()
Shapely Output:
对我来说有趣的是,当我使用 Matplotlib 创建线条时,一切都是正确的。
代码:
import cartopy.crs as ccrs
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(12, 8))
ax = fig.add_subplot(projection=ccrs.PlateCarree())
ax.stock_img()
org_lon, org_lat = cols["longitude_1"], cols["latitude_1"]
dst_lon, dst_lat = cols["longitude_2"], cols["latitude_2"]
plt.plot([org_lon, dst_lon], [org_lat, dst_lat],
color='black', linewidth=0.5, marker='_',
transform=ccrs.PlateCarree()
)
plt.savefig(f"fight_path.png",dpi=60,facecolor = None, bbox_inches = 'tight', pad_inches = None)
plt.show()
Matplotlib Output:
有什么问题?
为什么 shapely 不正确?
这就是您创建几何图形的方式。以下工作正常。
import io
import geopandas as gpd
import pandas as pd
import shapely.geometry
df = pd.read_csv(
io.StringIO(
"""callsign,latitude_1,longitude_1,latitude_2,longitude_2
HBAL102,-4.82114,-76.3194,-4.5249,-79.0103
AUA1028,-33.9635,151.181,48.1174,16.55
ABW120,41.9659,-87.8832,55.9835,37.4958
CSN461,33.9363,-118.414,50.0357,8.5723
ETH3730,25.3864,55.4221,50.6342,5.43903
"""
)
)
geoline = gpd.GeoDataFrame(
geometry=[
shapely.geometry.LineString(points)
for points in zip(
gpd.points_from_xy(df["longitude_1"], df["latitude_1"]),
gpd.points_from_xy(df["longitude_2"], df["latitude_2"]),
)
],
data=df,
)
import matplotlib.pyplot as plt
world = gpd.read_file(gpd.datasets.get_path("naturalearth_lowres"))
ax = world.plot(figsize=(14, 9), color="white", edgecolor="black")
geoline.plot(
figsize=(14, 9),
ax=ax,
facecolor="lightgrey",
linewidth=1.75,
edgecolor="red",
)
plt.show()
我想将始发地 (lat_1 lon_1) 的飞机连接到目的地 (lat_2 lon_2)。我使用 these 数据。
callsign | latitude_1 | longitude_1 | latitude_2 | longitude_2 | |
---|---|---|---|---|---|
0 | HBAL102 | -4.82114 | -76.3194 | -4.5249 | -79.0103 |
1 | AUA1028 | -33.9635 | 151.181 | 48.1174 | 16.55 |
2 | ABW120 | 41.9659 | -87.8832 | 55.9835 | 37.4958 |
3 | CSN461 | 33.9363 | -118.414 | 50.0357 | 8.5723 |
4 | ETH3730 | 25.3864 | 55.4221 | 50.6342 | 5.43903 |
但不幸的是,在使用 shapely 创建 LineString 时,我会得到不正确的结果。我使用了旋转和仿射等所有方法,但它没有正确。
代码:
cols = pd.read_csv("/content/dirct_lines.csv",sep=";")
line = cols[["callsign","latitude_1","longitude_1","latitude_2","longitude_2"]].dropna()
line['geometry'] = line.apply(lambda x: [(x['latitude_1'],
x['longitude_1']),
(x['latitude_2'],
x['longitude_2'])], axis = 1)
geoline = gpd.GeoDataFrame(line,geometry="geometry",
crs="EPSG:4326")
import matplotlib.pyplot as plt
world = gpd.read_file(gpd.datasets.get_path('naturalearth_lowres'))
ax = world.plot(figsize=(14,9),
color='white', edgecolor='black')
geoline.plot(figsize=(14,9),ax=ax,facecolor = 'lightgrey', linewidth = 1.75,
edgecolor = 'red',
alpha = 2)
plt.show()
Shapely Output:
对我来说有趣的是,当我使用 Matplotlib 创建线条时,一切都是正确的。
代码:
import cartopy.crs as ccrs
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(12, 8))
ax = fig.add_subplot(projection=ccrs.PlateCarree())
ax.stock_img()
org_lon, org_lat = cols["longitude_1"], cols["latitude_1"]
dst_lon, dst_lat = cols["longitude_2"], cols["latitude_2"]
plt.plot([org_lon, dst_lon], [org_lat, dst_lat],
color='black', linewidth=0.5, marker='_',
transform=ccrs.PlateCarree()
)
plt.savefig(f"fight_path.png",dpi=60,facecolor = None, bbox_inches = 'tight', pad_inches = None)
plt.show()
Matplotlib Output:
有什么问题?
为什么 shapely 不正确?
这就是您创建几何图形的方式。以下工作正常。
import io
import geopandas as gpd
import pandas as pd
import shapely.geometry
df = pd.read_csv(
io.StringIO(
"""callsign,latitude_1,longitude_1,latitude_2,longitude_2
HBAL102,-4.82114,-76.3194,-4.5249,-79.0103
AUA1028,-33.9635,151.181,48.1174,16.55
ABW120,41.9659,-87.8832,55.9835,37.4958
CSN461,33.9363,-118.414,50.0357,8.5723
ETH3730,25.3864,55.4221,50.6342,5.43903
"""
)
)
geoline = gpd.GeoDataFrame(
geometry=[
shapely.geometry.LineString(points)
for points in zip(
gpd.points_from_xy(df["longitude_1"], df["latitude_1"]),
gpd.points_from_xy(df["longitude_2"], df["latitude_2"]),
)
],
data=df,
)
import matplotlib.pyplot as plt
world = gpd.read_file(gpd.datasets.get_path("naturalearth_lowres"))
ax = world.plot(figsize=(14, 9), color="white", edgecolor="black")
geoline.plot(
figsize=(14, 9),
ax=ax,
facecolor="lightgrey",
linewidth=1.75,
edgecolor="red",
)
plt.show()