BASH

Question

我不知道如何向文件添加一行，然后只打印带有行号的那一行。这是我当前打印所有行的代码：

printf "Would you like to add an entry to the file? Type yes or y? "
read addline
input=$addline
if [ $input = 'yes' ] || [ $input = 'y' ]
then
    printf "Please enter a new name: First Last: "
    read newname
    printf "Please enter a new telephone number: xxx-xxx-xxxx: "
    read phone
    printf "Please enter a street address only: xxx Example Street: "
    read street
    printf "Please enter your birthdate: xx-xx-xxxx: "
    read birth
    printf "Please enter salary: xxxxxxx: "
    read salary
    echo -e "$newname:$phone:$street:$birth:$salary" >> datafile.txt
else
    printf "\nYou did not type yes or y. Run the program again.\n"
    exit
fi
printf "\nYour entry has been saved.\n" 
sort -k2 $file | nl

Answer 1

您可以使用 -n 选项 grep 打印匹配行及其行号。

grep -n -F -x "$newname:$phone:$street:$birth:$salary" datafile.txt

Answer 2

感谢 Barmar 的帮助，我找到了答案。

cat -n $文件 | grep "$newname:$phone:$street:$birth:$salary"

谢谢大家

BASH - 将包含行号的新条目打印到文件

BASH - Print new entry to file with line number included

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