如何从 Laravel 8 中的关系中过滤数据？

Question

我有 3 个表业务，服务，service_venues。我需要具有 service_name = $search 的业务服务，并获取所选服务的场所。我正在使用服务和资源方法。

当有 search_keyword 时，数据未被过滤。但其他条件正在发挥作用。我该如何解决这个问题？

商业模式

public function businessServices()
    {
        return $this->hasMany(BusinessService::class);
    }

在业务服务模型中

 public function businessServiceVenues()
    {
        return $this->hasMany(BusinessServiceVenue::class);
    }

在服务文件中

public function getServices($business){
       $businessservices =  $business->with(['businessServices'=> function ($q){
            $q->where('business_services.service_name', 'like', '%'.request()->search_key.'%');
        }
        ])->first();        
        return  new servicesResource($businessservices);
    }

在服务资源中

$services = $this->businessServices()
        ->with(['businessServiceStaffs','businessServiceVenues'])
        ->when(request()->filled('venue_ids'), function ($q) use($request) {
            $q->whereHas('businessServiceVenues', function($q1) use($request) {
                $q1->whereIn('venue_id',$request->venue_ids);
            });
          })
        ->when(request()->filled('staff_id'), function ($q) use($request) {
            $q->whereHas('businessServiceStaffs', function($q1) use($request) {
                $q1->where('staff_id','=',$request->staff_id);
            });
          })
        ->get();

Answer 1

这对我有用

$businessServices = $business->businessServices()
            ->with(['businessServiceStaffs', 'businessServiceVenues'])
            ->when(request()->filled('search_key'), function ($q) {
                $q->where('business_services.service_name', 'like', '%' . request('search_key') . '%');
            })
            ->when(request()->filled('venue_ids'), function ($q) {
                $q->whereHas('businessServiceVenues', function ($q) {
                    $q->whereIn('venue_id', request('venue_ids'));
                });
            })
            ->when(request()->filled('staff_id'), function ($q) {
                $q->whereHas('businessServiceStaffs', function ($q) {
                    $q->where('staff_id', '=', request('staff_id'));
                });
            })
            ->get();

如何从 Laravel 8 中的关系中过滤数据？

How can I filter data from relations in Laravel 8?

laravel

eloquent

laravel-resource