使用 Jolt 从 JSON 输出中删除空值

Question

您能否建议我一种从 json 输出中删除空值的方法，如下所述：

输入

{
  "userId": "1",
  "age": "20",
  "desc1": "value desc1",
  "desc2": "value desc2",
  "desc3": "value desc3",
  "desc4": "value desc4",
  "desc5": "value desc5",
  "desc6": "value desc6",
  "desc7": "value desc7"
}

规格

[
  {
    "operation": "shift",
    "spec": {
      "desc4": "test4",
      "desc5": "test5",
      "desc6": "test6",
      "desc1|desc2|desc3": {
        "$": "additionalInformationList[#2].typeCode",
        "@": "additionalInformationList[#2].value"
      }
    }
  }
]

输出

{
  "test4": "value desc4",
  "test5": "value desc5",
  "test6": "value desc6",
  "additionalInformationList": [null,null,null,
    {
      "typeCode": "desc1",
      "value": "value desc1"
    },
    {
      "typeCode": "desc2",
      "value": "value desc2"
    },
    {
      "typeCode": "desc3",
      "value": "value desc3"
    }
  ]
}

关于如何删除空值的任何建议？

Answer 1

确实够用

[
  {
    "operation": "shift",
    "spec": {
      "desc*": "&",
      "desc1|desc2|desc3": {
        "$": "additionalInformationList[#2].typeCode",
        "@": "additionalInformationList[#2].value"
      }
    }
  },
  {
    "operation": "remove",
    "spec": {
      "desc7": ""
    }
  }
]

如果您不使用 test 重命名 desc 属性以获得

{
  "additionalInformationList" : [ {
    "typeCode" : "desc1",
    "value" : "value desc1"
  }, {
    "typeCode" : "desc2",
    "value" : "value desc2"
  }, {
    "typeCode" : "desc3",
    "value" : "value desc3"
  } ],
  "desc4" : "value desc4",
  "desc5" : "value desc5",
  "desc6" : "value desc6"
}

对于目前的情况，可以使用

[
  {
    "operation": "shift",
    "spec": {
      "desc*": "test&",
      "desc1|desc2|desc3": {
        "$": "additionalInformationList[#2].typeCode",
        "@": "additionalInformationList[#2].value"
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "test*": {
        "$": "@(0)"
      },
      "*": "&"
    }
  },
  {
    "operation": "modify-overwrite-beta",
    "spec": {
      "*desc*": "=split('desc',@(1,&))"
    }
  },
  {
    "operation": "modify-overwrite-beta",
    "spec": {
      "*desc*": "=join('',@(1,&))"
    }
  },
  {
    "operation": "shift",
    "spec": {
      "*desc*": {
        "$": "@(0)"
      },
      "*": "&"
    }
  },
  {
    "operation": "remove",
    "spec": {
      "test7": ""
    }
  }
]

或更短的大小写，分别写入 desc4、desc5 和 desc6[=33 的键值对=] 属性可能是

[ { "operation": "shift", "spec": { "desc4": "test4", "desc5": "test5", "desc6": "test6", "desc*": { "$": "&.code", "@": "&.value" } } }, { "operation": "remove", "spec": { "desc7": "" } }, { "operation": "shift", "spec": { "test*": "&", "*": "additionalInformation[]" } } ]

使用 Jolt 从 JSON 输出中删除空值

Remove null values from JSON output using Jolt

java

json

jolt