如何列出列表的元素

Question

我必须列出一个列表的元素。我有清单： n=[1,2,3,4,5,6] 我想创建：

n=[[1],[2],[3],[4],[5],[6]]
n=[[1,2],[3,4],[5,6]]
n=[[1,2,3],[4,5,6]]

我可以使用 map(list,n) 做第一个，但是其他的呢？另外，如果我想为每对元素创建一个列表，例如：

n=[[1,2] [2,3] [3,4] [4,5] [5,6]]

我该怎么做？

Answer 1

>>> s = [1,2,3,4,5,6]
>>> s1 = [[each] for each in s]
>>> s1
[[1], [2], [3], [4], [5], [6]]

>>> s2 = [[each,each+1] for each in s[:2:]]
>>> s2

[[1, 2], [2, 3]]
>>> s2 = [[each,each+1] for each in s[::2]]
>>> s2
[[1, 2], [3, 4], [5, 6]]
>>> s2 = [[each, each+1, each+2] for each in s[::3]]
>>> s2

[[1, 2, 3], [4, 5, 6]]
>>>

Answer 2

您可以使用一些列表理解、iter 和 zip 技巧来使用 chunkify 方法：

def chunkify(l, size):
    it = iter(l)
    return [list(e) for e in zip(*[it for _ in range(size)])]

示例：

n=[1,2,3,4,5,6]
for size in range(1, 4):
    print(chunkify(n, size))

输出：

[[1], [2], [3], [4], [5], [6]]
[[1, 2], [3, 4], [5, 6]]
[[1, 2, 3], [4, 5, 6]]

如何列出列表的元素

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