使用第一列比较两个文件，在将列附加到输出时打印差异

Question

我有两个要比较的制表符分隔文件。

我想查找 file1 中 col1 中 file2 中缺失的值（前缀为“left”）和 file2 中 col1 中 file1 中缺失的值（前缀为“joined”）。对于这些行，我想打印 col1 和 col8。我的 diff 命令对于 col1 值相等而 col8 值不同的行失败。

文件 1:

Char1   55  Necromancer Knight  A   11/21/21    Zone    Char1(Main)     off off 0       Char1(Main) 
Char2   28  Druid   Squire  A   12/08/21    Zone    Char1       off off 0       Char1   
Char3   44  Enchanter   Recruit A   08/07/21    Zone    Char3(Main)     off off 0       Char3(Main) 
Char4   56  Enchanter   Knight  A   11/06/21    Zone    Char4(Main)     off off 0       Char4(Main) 
Char5   10  Magician    Recruit A   10/29/21    Zone    Char1       off off 0       Char1   
Char6   65  Druid   Champion    A   12/12/21    The Lair of the Splitpaw    Char6(Main) VT emp time     off off 0       Char6(Main) VT emp time

文件 2:

Char1   55  Necromancer Knight  A   11/21/21    Zone    Char1(Main)     off off 0       Char1(Main) 
Char2   28  Druid   Squire  A   12/08/21    Zone    Char1       off off 0       Char1   
Char3   44  Enchanter   Recruit A   08/07/21    Zone    Char3(Main)     off off 0       Char3(Main) 
Char4   56  Enchanter   Knight  A   11/06/21    Zone    Char4(Main)     off off 0       Char4(Main) 
Char5a  10  Magician    Recruit A   10/29/21    Zone    Char1       off off 0       Char1   
Char6   65  Druid   Champion    A   12/21/21    Zone    Char6(Main) Emp/VT/Time     off off 0       Char6(Main) Emp/VT/Time

diff 命令产生输出：

diff --new-line-format="joined %L" --old-line-format="left %L" --unchanged-line-format="" <(cut -f1,8 "$file1" | sort) <(cut -f1,8 "$file2" | sort) | sort

当前输出：

joined Char5a   Char1
joined Char6    Char6(Main) Emp/VT/Time
left Char5      Char1
left Char6      Char6(Main) VT emp time

期望的输出：

joined Char5a   Char1
left Char5      Char1

非常感谢任何帮助，谢谢！

Answer 1

希望这个 python 脚本能达到您的期望：

#!/bin/bash

python -c '
import re, sys
def read_into_dict(regex, file):
    return { re.findall(regex, line)[0]: line for line in open(file) }
regex, file1, file2 = sys.argv[1:]
dict1 = read_into_dict(regex, file1)
dict2 = read_into_dict(regex, file2)
keys1 = set(dict1.keys())
keys2 = set(dict2.keys())
for key in (keys1 - keys2):
    print(f"left {dict1[key]}")
for key in (keys2 - keys1):
    print(f"joined {dict2[key]}")
' '^(\S+)' <(cut -f1,8 "$file1" | sort) <(cut -f1,8 "$file2" | sort) | sort

Answer 2

Diff 用于简单的差异。使用 awk.
更容易解决您的问题您不需要对文件进行排序，只需读取两个文件并计算第 1 列中的键出现的频率。
在计算关键值时准备潜在的输出。当 NR==FNR 你在第一个文件中并且你想使用 "left".
读取两个文件后，查找仅出现一次的键并打印该行的准备输出。

awk -F'\t' '
  {
    key[]++
    value[]=(NR==FNR ? "left " : "joined ")  "\t" 
  }
  END { 
    for (i in key) { 
      if (key[i]==1) { 
        print value[i]
      }
    }
  }' file1 file2

使用第一列比较两个文件，在将列附加到输出时打印差异

Compare two files using first column, print diff while appending column to output

bash

unix

awk

diff