"on HttpException catch (error)" 在 flutter 中不起作用
"on HttpException catch (error)" desn't work in flutter
我编写了这段代码来处理来自服务器 Firebase 的 flutter 错误:
这是主要功能:
try {
if (_authMode == AuthMode.Login) {
print("log in");
await Provider.of<Auth>(context, listen: false)
.signIn(_authData['email'], _authData['password']);
} else {
await Provider.of<Auth>(context, listen: false)
.signUp(_authData['email'], _authData['password']);
}
} on HttpException catch (error) {
print("Check error");
if (error.toString().contains("EMAIL_EXISTS")) {
_ServerError =
"The email address is already in use by another account.";
}
if (error.toString().contains("TOO_MANY_ATTEMPTS_TRY_LATER")) {
_ServerError =
"We have blocked all requests from this device due to unusual activity.\n Try again later.";
} else {
_ServerError = "Something wrong. \n Try again later!";
}
} catch (error) {
print(error.toString() );
}
这是被调用的函数:
Future<void> signIn(String? email, String? password) async {
const _url =
"https://identitytoolkit.googleapis.com/v1/accounts:signInWithPassword?key=APICODE";
_authentication(_url, email, password);}
Future<void> _authentication(
String _url, String? email, String? password) async {
try {
final _response = await http.post(Uri.parse(_url),
body: json.encode({
'email': email,
'password': password,
'returnSecureToken': true
}));
final _responseData = json.decode(_response.body);
if (_responseData['error'] != null) {
throw HttpException(_responseData['error']['message']);
}
} catch (error) {
throw error;
}}
但问题是当被调用的函数抛出 HttpException 错误时,我没有在主函数中得到它,因为 Catch 不起作用,因为我没有在面板中得到消息“检查错误” ?!
这是面板:
你能帮帮我吗?
问题是我忘记将 return 添加到调用的函数中:
Future<void> signIn(String? email, String? password) async {
const _url =
"https://identitytoolkit.googleapis.com/v1/accounts:signInWithPassword?key=APICODE";
return _authentication(_url, email, password);
}
我编写了这段代码来处理来自服务器 Firebase 的 flutter 错误:
这是主要功能:
try {
if (_authMode == AuthMode.Login) {
print("log in");
await Provider.of<Auth>(context, listen: false)
.signIn(_authData['email'], _authData['password']);
} else {
await Provider.of<Auth>(context, listen: false)
.signUp(_authData['email'], _authData['password']);
}
} on HttpException catch (error) {
print("Check error");
if (error.toString().contains("EMAIL_EXISTS")) {
_ServerError =
"The email address is already in use by another account.";
}
if (error.toString().contains("TOO_MANY_ATTEMPTS_TRY_LATER")) {
_ServerError =
"We have blocked all requests from this device due to unusual activity.\n Try again later.";
} else {
_ServerError = "Something wrong. \n Try again later!";
}
} catch (error) {
print(error.toString() );
}
这是被调用的函数:
Future<void> signIn(String? email, String? password) async {
const _url =
"https://identitytoolkit.googleapis.com/v1/accounts:signInWithPassword?key=APICODE";
_authentication(_url, email, password);}
Future<void> _authentication(
String _url, String? email, String? password) async {
try {
final _response = await http.post(Uri.parse(_url),
body: json.encode({
'email': email,
'password': password,
'returnSecureToken': true
}));
final _responseData = json.decode(_response.body);
if (_responseData['error'] != null) {
throw HttpException(_responseData['error']['message']);
}
} catch (error) {
throw error;
}}
但问题是当被调用的函数抛出 HttpException 错误时,我没有在主函数中得到它,因为 Catch 不起作用,因为我没有在面板中得到消息“检查错误” ?!
这是面板:
问题是我忘记将 return 添加到调用的函数中:
Future<void> signIn(String? email, String? password) async {
const _url =
"https://identitytoolkit.googleapis.com/v1/accounts:signInWithPassword?key=APICODE";
return _authentication(_url, email, password);
}