如何使用 django-filters 过滤 ModelViewSet 中的自定义 url

Question

class ExportTabView(ModelViewSet):
    permission_classes = [UserHasDatasetChangeAccess]
    queryset = JobTable.objects.all()
    filterset_fields = [
        "job_type",
        "action",
        "source_table__name",
        "source_table__type",
    ]
    ordering_fields = ["created_on", "modified_on"]
    ordering = ["-modified_on"]

我可以使用上述 api 的 django 过滤器作为 :

/api/export-tab-view?source_table__name='temp'

但是在这个模型视图集中添加自定义 url 后，我无法使用 django 过滤器。

class ExportTabView(ModelViewSet):
    serializer_class = ExportTabSerializer
    permission_classes = [UserHasDatasetChangeAccess]
    queryset = JobTable.objects.all()
    filterset_fields = [
        "job_type",
        "action",
        "source_table__name",
        "source_table__type",
    ]
    ordering_fields = ["created_on", "modified_on"]
    ordering = ["-modified_on"]

    @action(detail=False)
    def export_dataset(self, request, id=None):
    """
    Returns a list of all the relationship names that the given
    dataset has
    """
        jobs = JobTable.objects.filter(
        dataset=get_object_or_404(DataSet, id=self.request.META.get(DATASET_ID, ""))
        )
        return Response(ExportTabSerializer(jobs, many=True).data)

现在当我调用 api

时过滤器不起作用

/api/export-tab-view/export_dataset?source_table__name='temp'

Answer 1

您可以通过这样做过滤数据集，但这取决于您要查询的 DataSet 对象的哪个字段！我猜你是否想假设字段名称来制作数据集模型的查询集是数据集，像这样将它提供给过滤器：

 @action(detail=False)
    def export_dataset(self, request, id=None):
    """
    Returns a list of all the relationship names that the given
    dataset has
    """ 
        dataset=get_object_or_404(DataSet id=self.request.META.get(DATASET_ID, ""), **dict(request.query_params.items()))
        jobs = JobTable.objects.filter(dataset=dataset)
        return Response(ExportTabSerializer(jobs, many=True).data)

Answer 2

我已经这样做了，目前效果很好。

@action(detail=False)
def export_dataset(self, request, id=None):
    """
    Returns a list of all the relationship names that the given
    dataset has
    """
    jobs = JobTable.objects.filter(
        dataset=get_object_or_404(DataSet, id=self.request.META.get(DATASET_ID, "")),
    **dict(request.query_params.items()))
    return Response(ExportTabSerializer(jobs, many=True).data)

如何使用 django-filters 过滤 ModelViewSet 中的自定义 url

How to filter custom urls in ModelViewSet with django-filters

django

django-filters