只有月份和年份的 Unix 时间戳

Question

我有一组不同的日期，但它们只包括月份和年份。有没有办法从这两件事中获取 unix 时间戳？我必须遍历数组以获取所有时间戳。我有解决方案，但解决方案又丑又长。有没有 simpler/easier 方法来减少我的代码量？

for(var i=0, len = arr.length; i < len; i++){
        arr[i]['newDate'] = [];
        var jan = day * 31;
        var year = 31556926;
        var day = 86400;
        if(arr[i].post_date.includes("Janurary")){
            //january
            var str = arr[i].post_date.substr(8);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = jan + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("February")){
            //february
            var str = arr[i].post_date.substr(8);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = feb + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("March")){
            //march
            var str = arr[i].post_date.substr(6);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = mar + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("April")){
            //april
            var str = arr[i].post_date.substr(6);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = apr + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("May")){
            //may
            var str = arr[i].post_date.substr(4);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = may + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("June")){
            //june
            var str = arr[i].post_date.substr(5);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = jun + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("July")){
            //july
            var str = arr[i].post_date.substr(5);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = jul + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("August")){
            //august
            var str = arr[i].post_date.substr(7);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = aug + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("September")){
            //september
            var str = arr[i].post_date.substr(10);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = sep + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("October")){
            //october
            var str = arr[i].post_date.substr(8);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = oct + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("November")){
            //november
            var str = arr[i].post_date.substr(9);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = nov + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }
        if(arr[i].post_date.includes("December")){
            //december
            var str = arr[i].post_date.substr(9);
            var current = parseInt(str);
            var yearTotal = (current - 1970) * year;
            var unix = dec + yearTotal;
            var dateString = "@" + unix.toString();
            arr[i].newDate.push(dateString);
        }

        var jan = day * 31;
        var feb = day * 28;
        var mar = day * 31;
        var apr = day * 30;
        var may = day * 31;
        var jun = day * 30;
        var jul = day * 31;
        var aug = day * 31;
        var sep = day * 30;
        var oct = day * 31;
        var nov = day * 30;
        var dec = day * 31; 
    }

我的数组看起来像这样

var arr = [
    {
      "post_title": "title",
      "post_date": "December 2021"
    },
    {
      "post_title": "title",
      "post_date": "November 2021"
    },
    {
      "post_title": "title",
      "post_date": "October 2021"
    },
    {
      "post_title": "title",
      "post_date": "September 2021"
    },
    {
      "post_title": "title",
      "post_date": "August 2021"
    },
    {
      "post_title": "title",
      "post_date": "July 2021"
    },
    {
      "post_title": "title",
      "post_date": "June 2021"
    }
]

我的结果看起来像

var arr = [
    {
      "post_title": "title",
      "post_date": "December 2021",
      "newDate": [
        "@1612081626"
      ]
    },
    {
      "post_title": "title",
      "post_date": "November 2021",
      "newDate": [
        "@1611995226"
      ]
    },
    {
      "post_title": "title",
      "post_date": "October 2021",
      "newDate": [
        "@1612081626"
      ]
    },
    {
      "post_title": "title",
      "post_date": "September 2021",
      "newDate": [
        "@1611995226"
      ]
    },
    {
      "post_title": "title",
      "post_date": "August 2021",
      "newDate": [
        "@1612081626"
      ]
    },
    {
      "post_title": "title",
      "post_date": "July 2021",
      "newDate": [
        "@1612081626"
      ]
    },
    {
      "post_title": "title",
      "post_date": "June 2021",
      "newDate": [
        "@1611995226"
      ]
    }
]

Answer 1

您可以使用字符串中的月份（转换为索引）和年份简单地创建 new Date()。

此处使用月份数组将命名月份转换为索引，并将结果除以 1000，因为 javascript 以毫秒为单位存储时间，而 unix 使用秒。

const arr = [{ post_title: 'title', post_date: 'December 2021', }, { post_title: 'title', post_date: 'November 2021', }, { post_title: 'title', post_date: 'October 2021', }, { post_title: 'title', post_date: 'September 2021', }, { post_title: 'title', post_date: 'August 2021', }, { post_title: 'title', post_date: 'July 2021', }, { post_title: 'title', post_date: 'June 2021', },];

const months = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December',]; 

const result = arr.map((o) => {
  const [month, year] = o.post_date.split(' ');

  return {
    ...o,
    unix_timestamp: new Date(year, months.indexOf(month)).valueOf() / 1000,
  };
});

console.log(result);

注意：月份是 0 索引，从一月的 0 到十二月的 11

Answer 2

你真的不需要查找 table:

const arr = [{ post_title: 'title', post_date: 'December 2021', }, { post_title: 'title', post_date: 'November 2021', }, { post_title: 'title', post_date: 'October 2021', }, { post_title: 'title', post_date: 'September 2021', }, { post_title: 'title', post_date: 'August 2021', }, { post_title: 'title', post_date: 'July 2021', }, { post_title: 'title', post_date: 'June 2021', },];

const result = arr.map(d =>
    ({...d,
    unix_timestamp: new Date(d.post_date.replace(" "," 1. ")+" 00:00:00").valueOf() / 1000}));

console.log(result);

只有月份和年份的 Unix 时间戳

Unix timestamp with only month and year

javascript

unix

arrays

unix-timestamp

scrape