如何正确初始化另一个结构中的结构数组并从函数 return 中初始化它?
How to properly initialize array of structures inside another structure and return it from function?
我有一个这样的结构数组:
typedef struct month {
char cName[20];
char cAbbr[20];
int iDays;
int iNumber;
} MONTH;
嵌套在另一个结构中:
typedef struct input{
MONTH * pMonths;
DATE sDate;
CALCS sCalcs;
} INPUT;
我这样在堆栈中初始化这个结构数组:
MONTH * init_months(bool bLeap) {
MONTH months[NUM_MONTHS] = {
{ .cName = "January", .cAbbr = "Jan", .iDays = 31, .iNumber = 1 },
{ "February", "Feb", 28, 2 },
{ "March", "Mar", 31, 3 },
{ "April", "Apr", 30, 4 },
{ "May", "May", 31, 5 },
{ "June", "Jun", 30, 6 },
{ "July", "Jul", 31, 7 },
{ "August", "Aug", 31, 8 },
{ "September", "Sep", 30, 9 },
{ "October", "Oct", 31, 10 },
{ "November", "Nov", 30, 11 },
{ "December", "Dec", 31, 12 }
};
if(bLeap){
months[1].iDays++;
}
return months;
}
问题是,如果我在某个函数中形成一个 INPUT 结构:
INPUT GetUserInput(void){
// init months
MONTH * pMonths;
pMonths = init_months(isLeap(sDate.iYear));
// some code here
...
INPUT sInput = { pMonths, sDate, sCalcs };
// return
return sInput;
}
然后如何正确初始化 MONTH 数组 and/or 如何正确初始化 INPUT 以便它在以下情况下包含有效数据从 GetUserInput() 返回?
您有 3 个选项:
- 使其成为静态的(但所有 returned 引用将引用同一个数组)。
static MONTH months[NUM_MONTHS] = {
- 使用 malloc 和复合文字
MONTH *months = malloc(sizeof(*months) * NUM_MONTHS);
/* check if memory was allocated */
memcpy(months, (MONTH[]){
{ .cName = "January", .cAbbr = "Jan", .iDays = 31, .iNumber = 1 },
{ "February", "Feb", 28, 2 },
{ "March", "Mar", 31, 3 },
{ "April", "Apr", 30, 4 },
{ "May", "May", 31, 5 },
{ "June", "Jun", 30, 6 },
{ "July", "Jul", 31, 7 },
{ "August", "Aug", 31, 8 },
{ "September", "Sep", 30, 9 },
{ "October", "Oct", 31, 10 },
{ "November", "Nov", 30, 11 },
{ "December", "Dec", 31, 12 }}, sizeof(*months) * NUM_MONTHS);
- 将table包装到另一个结构中并return按值
typedef struct
{
MONTH months[NUM_MONTHS];
}YEAR;
YEAR init_months(bool bLeap) {
YEAR year = {{
{ .cName = "January", .cAbbr = "Jan", .iDays = 31, .iNumber = 1 },
{ "February", "Feb", 28, 2 },
{ "March", "Mar", 31, 3 },
{ "April", "Apr", 30, 4 },
{ "May", "May", 31, 5 },
{ "June", "Jun", 30, 6 },
{ "July", "Jul", 31, 7 },
{ "August", "Aug", 31, 8 },
{ "September", "Sep", 30, 9 },
{ "October", "Oct", 31, 10 },
{ "November", "Nov", 30, 11 },
{ "December", "Dec", 31, 12 }}};
if(bLeap){
year.months[1].iDays++;
}
return year;
}
我有一个这样的结构数组:
typedef struct month {
char cName[20];
char cAbbr[20];
int iDays;
int iNumber;
} MONTH;
嵌套在另一个结构中:
typedef struct input{
MONTH * pMonths;
DATE sDate;
CALCS sCalcs;
} INPUT;
我这样在堆栈中初始化这个结构数组:
MONTH * init_months(bool bLeap) {
MONTH months[NUM_MONTHS] = {
{ .cName = "January", .cAbbr = "Jan", .iDays = 31, .iNumber = 1 },
{ "February", "Feb", 28, 2 },
{ "March", "Mar", 31, 3 },
{ "April", "Apr", 30, 4 },
{ "May", "May", 31, 5 },
{ "June", "Jun", 30, 6 },
{ "July", "Jul", 31, 7 },
{ "August", "Aug", 31, 8 },
{ "September", "Sep", 30, 9 },
{ "October", "Oct", 31, 10 },
{ "November", "Nov", 30, 11 },
{ "December", "Dec", 31, 12 }
};
if(bLeap){
months[1].iDays++;
}
return months;
}
问题是,如果我在某个函数中形成一个 INPUT 结构:
INPUT GetUserInput(void){
// init months
MONTH * pMonths;
pMonths = init_months(isLeap(sDate.iYear));
// some code here
...
INPUT sInput = { pMonths, sDate, sCalcs };
// return
return sInput;
}
然后如何正确初始化 MONTH 数组 and/or 如何正确初始化 INPUT 以便它在以下情况下包含有效数据从 GetUserInput() 返回?
您有 3 个选项:
- 使其成为静态的(但所有 returned 引用将引用同一个数组)。
static MONTH months[NUM_MONTHS] = {
- 使用 malloc 和复合文字
MONTH *months = malloc(sizeof(*months) * NUM_MONTHS);
/* check if memory was allocated */
memcpy(months, (MONTH[]){
{ .cName = "January", .cAbbr = "Jan", .iDays = 31, .iNumber = 1 },
{ "February", "Feb", 28, 2 },
{ "March", "Mar", 31, 3 },
{ "April", "Apr", 30, 4 },
{ "May", "May", 31, 5 },
{ "June", "Jun", 30, 6 },
{ "July", "Jul", 31, 7 },
{ "August", "Aug", 31, 8 },
{ "September", "Sep", 30, 9 },
{ "October", "Oct", 31, 10 },
{ "November", "Nov", 30, 11 },
{ "December", "Dec", 31, 12 }}, sizeof(*months) * NUM_MONTHS);
- 将table包装到另一个结构中并return按值
typedef struct
{
MONTH months[NUM_MONTHS];
}YEAR;
YEAR init_months(bool bLeap) {
YEAR year = {{
{ .cName = "January", .cAbbr = "Jan", .iDays = 31, .iNumber = 1 },
{ "February", "Feb", 28, 2 },
{ "March", "Mar", 31, 3 },
{ "April", "Apr", 30, 4 },
{ "May", "May", 31, 5 },
{ "June", "Jun", 30, 6 },
{ "July", "Jul", 31, 7 },
{ "August", "Aug", 31, 8 },
{ "September", "Sep", 30, 9 },
{ "October", "Oct", 31, 10 },
{ "November", "Nov", 30, 11 },
{ "December", "Dec", 31, 12 }}};
if(bLeap){
year.months[1].iDays++;
}
return year;
}