如何 return 基于 es6 中对象的 id 的唯一对象数组？

Question

    Array(96) [ {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, {…}, … ]

0: Object { id: 1, name: "PrimShal01", period: 3, … }
1: Object { id: 61, name: "TertDeep01", period: 1, … }
2: Object { id: 37, name: "SecoDeep01", period: 2, … }
3: Object { id: 49, name: "TertShal01", period: 1, … } 
4: Object { id: 13, name: "PrimDeep01", period: 3, … }
5: Object { id: 61, name: "TertDeep01", period: 1, … }

当我尝试以下代码时，我只获得了唯一 ID，但我想要对象：

const uniques = [new Set(all_filter_ids.map(pos => pos.id))]

当我尝试下面的代码时，我得到的结果和以前一样：

const uniques = [new Set(all_filter_ids)]

Answer 1

将它们变成一个以ID为索引的Map（一个键只能存在一个对象），然后将Map的值转回数组。

const map = new Map(all_filter_ids.map(pos => [pos.id, pos]));
const uniques = [...map.values()];

Answer 2

另一种解决方案：

const arr = [{ id: 1, name: "PrimShal01", period: 3},{ id: 61, name: "TertDeep01", period: 1},{ id: 37, name: "SecoDeep01", period: 2},{ id: 49, name: "TertShal01", period: 1},{ id: 13, name: "PrimDeep01", period: 3},{ id: 61, name: "TertDeep01", period: 1}]

const result = Object.values(
    arr.reduce((acc, obj) => ({ ...acc, [obj.id]: obj }), {})
);

console.log(result);

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Answer 3

维护一个 set 用于跟踪 ID 并使用 filter

const uniq = (arr, track = new Set()) =>
  arr.filter(({ id }) => (track.has(id) ? false : track.add(id)));

const arr = [
  { id: 1, name: "PrimShal01", period: 3 },
  { id: 61, name: "TertDeep01", period: 1 },
  { id: 37, name: "SecoDeep01", period: 2 },
  { id: 49, name: "TertShal01", period: 1 },
  { id: 13, name: "PrimDeep01", period: 3 },
  { id: 61, name: "TertDeep01", period: 1 },
];

console.log(uniq(arr))

如何 return 基于 es6 中对象的 id 的唯一对象数组？

How to return an array of unique objects based on the id of the object in es6?

javascript

arrays

unique

object

ecmascript-6